Question

The specific heat of copper is 0.385 J/g•°C. Which equation would you use to calculate the amount of heat needed to raise the temperature of 0.75 g of aluminum from 7°C to 29°C? Q = 0.75 g x 0.897 J/g•°C x 29°C Q = 0.75 g x 0.385 J/g•°C x 22°C Q = 0.75 g x 0.385 J/g•°C x 29°C Q = 0.75 g x 0.897 J/g•°C x 22°C

Answer 1

Answer:

Q = 0.75 g x 0.897 J/g•°C x 22°C

Explanation:

The amount of heat needed to raise the temperature of a substance is given by the equation

$Q=m C \Delta T$

where

m is the mass of the substance

C is the specific heat capacity

$\Delta T$ is the increase in temperature of the substance

In this problem, the mass of the aluminium is m=0.75 g. The specific heat of aluminium is C=0.897 J/g•°C, while the increase in temperature is

$\Delta T=29^{\circ}-7^{\circ}=22 ^{\circ}$

So, the equation becomes

Q = 0.75 g x 0.897 J/g•°C x 22°C

Answer 2

The amount of heat needed to raise the temperature is :

Q = 0.75 g × 0.897 J/g•°C × 22°C ≈ 14.8 J

$\texttt{ }$

Further explanation

Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

$\large {\boxed{Q = m \times c \times \Delta t} }$

Q = Energy ( Joule )

m = Mass ( kg )

c = Specific Heat Capacity ( J / kg°C )

Δt = Change In Temperature ( °C )

Let us now tackle the problem!

$\texttt{ }$

Given:

mass of aluminium = m = 0.75 g

change in temperature = Δt = 29 - 7 = 22°C

specific heat capacity of copper = c_copper = 0.385 J/g°C

specifc heat capacity of aluminium = c_aluminium = 0.897 J/g°C

Asked:

heat required = Q = ?

Solution:

$Q = m c_{aluminium} \Delta t$

$\boxed{Q = 0.75\texttt{ g} \times 0.897\texttt{ J/g.}^o\texttt{C} \times 22 ~^o\texttt{C}}$

$Q = 14.8 \texttt{ Joules}$

$\texttt{ }$

Conclusion:

The amount of heat needed to raise the temperature is :

Q = 0.75 g × 0.897 J/g•°C × 22°C ≈ 14.8 J

$\texttt{ }$

Learn more

• Efficiency of Engine : brainly.com/question/5597682
• Flow of Heat : brainly.com/question/3010079
• Difference Between Temperature and Heat : brainly.com/question/3821712

$\texttt{ }$

Answer details

Grade: College

Subject: Physics

Chapter: Thermal Physics