Answer:
Explanation:
Force on the electron = q ( v x B )
q = - 1.6 x 10⁻¹⁹
v = (5.9i−6.4j)×10⁴
B = (−0.63i+0.65j)
v x B = (5.9i−6.4j)×10⁴ x (−0.63i+0.65j)
= (3.835 - 4.032 ) x 10⁴ k
= - 1970 k
Force on the electron = q ( v x B )
= - 1.6 x 10⁻¹⁹ x -1970 k
= 3.152 x 10⁻¹⁶ k
z-component of the force on the electron
Fz = 3.152 x 10⁻¹⁶ N
Answer:
The magnetic poles are the places on the earth's surface where the magnetic field force is acting perpendicularly to the surface. The North magnetic pole is where the field is acting straight down; at the South magnetic pole, it is acting straight up.
Explanation:
As here it is given that
x = 150 m
a= 2 m/s^2
now initial speed of the plane must be zero as it start from rest
now we will use kinematics
so its final speed is maximum 24.5 m/s
so it will not reach to desired speed at the end of runway
Answer: 2Mg/k
Explanation:
Let a be the extension experienced by the spring when a mass M is released from rest. And k is the force constant value
The potential energy lost by the mass is equal to that gained by the spring.
The potential energy lost by the mass = M x g x a
The energy gained by the spring = 1/2 x K x a^2
Therefore, M x g x a = 1/2 x K x a^2
Mga = Ka^2/2
2Mga = ka^2
Making a the subject of the formula,
Dividing through by a,
2Mg = ka
Therefore, a = 2Mg/k
The maximum extension produced in the length of the spring will be 2Mg/k.
Answer:
1500kg
Explanation:
Assuming that the women push the car in the same direction, then the total force is:
Fnet = 425 N ⋅ 3
= 1275 N
To find the mass, we use Newton's second law of motion, which states that,
F = ma
where:
·F is the force applied in newtons
·m is the mass of the object in kilograms
·a is the acceleration of the object in meters per second squared.
So we get:
F
m= ⁻⁻⁻⁻⁻
a
1275N
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
0.85 m/s²
= 1500 kg
