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3 years ago

Explain, step by step, how to calculate the amount of current (I) that will go through the resistor in this circuit

Physics

2 answers:

stepan [7]3 years ago

8 0

Answer:

0.03 A

Explanation:

Explain, step by step, how to calculate the amount of current (I) that will go through the resistor in this circuit

0.03 A

anygoal [31]3 years ago

3 0

Answer:

0.03 A

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12 V

Resistor (R) = 470 Ω

Current (I) =?

From ohm's law, the voltage, current and resistor are related by the following formula:

Voltage = current × resistor

V = IR

With the above formula, we can obtain the current in the circuit as follow:

Voltage (V) = 12 V

Resistor (R) = 470 Ω

Current (I) =?

V = IR

12 = I × 470

Divide both side by 470

I = 12 / 470

I = 0.03 A

Thus, the current in the circuit is 0.03 A

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The expression below was formed by combining different gas laws.

kap26 [50]

Answer:

Avogadro's law.

Explanation:

Avogadro’s law states that, equal volumes of all gases at the same temperature and pressure contain the same number of molecules.

Mathematically,

V n

V = Kn where V = volume in cm3, dm3, ml or L; n = number of moles of gas;

K = mathematical constant.

The ideal gas equation is a combination of Boyle's law, Charles' law and Avogadro’s law.

V 1/P at constant temperature (Boyle’s law)

V T at constant pressure ( Charles’law)

V n at constant temperature and pressure ( Avogadro’s law )

Combining the equations yields,

V nT/P

Introducing a constant,

V = nRT/P

PV = nRT

Where P = pressure in atm, Pa, torr, mmHg or Nm-2; V = volume in cm3, dm3, ml or L; T = temperature in Kelvin; n = number of moles of gas in mol; R = molar gas constant = 0.082 dm3atmK-1mol-1

7 0

4 years ago

A 1.10 μF capacitor is connected in series with a 1.92 μF capacitor. The 1.10 μF capacitor carries a charge of +10.1 μC on one p

miss Akunina [59]

Answer:

(a). The potential on the negative plate is 42.32 V.

(b). The equivalent capacitance of the two capacitors is 0.69 μF.

Explanation:

Given that,

Charge = 10.1 μC

Capacitor C₁ = 1.10 μF

Capacitor C₂ = 1.92 μF

Capacitor C₃ = 1.10 μF

Potential V₁ = 51.5 V

Let V₁ and V₂ be the potentials on the two plates of the capacitor.

(a). We need to calculate the potential on the negative plate of the 1.10 μF capacitor

Using formula of potential difference

$V_{1}=\dfrac{Q}{C_{1}}$

Put the value into the formula

$V_{1}=\dfrac{10.1 \times10^{-6}}{1.10\times10^{-6}}$

$V_{1}=9.18\ V$

The potential on the second plate

$V_{2}=V-V_{1}$

$V_{2}=51.5 -9.18$

$V_{2}=42.32\ v$

(b). We need to calculate the equivalent capacitance of the two capacitors

Using formula of equivalent capacitance

$C=\dfrac{C_{1}\timesC_{2}}{C_{1}+C_{2}}$

Put the value into the formula

$C=\dfrac{1.10\times10^{-6}\times1.92\times10^{-6}}{(1.10+1.92)\times10^{-6}}$

$C=6.99\times10^{-7}\ F$

$C=0.69\ \mu F$

Hence, (a). The potential on the negative plate is 42.32 V.

(b). The equivalent capacitance of the two capacitors is 0.69 μF.

7 0

3 years ago

An object's buoyant force and weight mean the same thing. A. True B. False

german

Answer:

False

Explanation:

No. The buoyant force on an object is the portion of its weight that appears to vanish

when the object is in any fluid (could be either a liquid or a gas).

If the object happens to float in a particular fluid, then the buoyant force at that moment

is equal to the object's weight.

Notice that the buoyant force on an object will be different in different fluids.

6 0

3 years ago

A. Una onda armónica que se propaga por un medio unidimensional tiene una frecuencia de 500Hz y una velocidad de propagación de

Natasha2012 [34]

Answer:

0.117 m

Explanation:

First of all, we can find the wavelength of the wave in the problem, by using the wave equation:

$v=f\lambda$

where:

v = 350 m/s is the speed of the wave

f = 500 Hz is the frequency of the wave

$\lambda$ is the wavelength

Solving for $\lambda$ ,

$\lambda=\frac{v}{f}=\frac{350}{500}=0.7 m$

This means that the distance between two consecutive points of the wave having a difference of phase of

$\phi=2\pi$

is 0.7 m.

Here we want to find the distance between two points that have a difference of phase of

$\phi'=\frac{\pi}{3}$

So, we can set up the following rule of three:

$\frac{d}{\phi}=\frac{d'}{\phi'}$

where d' is the distance we are looking for. Solving for d',

$d'=d\frac{\phi'}{\phi}=(0.7)\frac{\pi/3}{2\pi}=\frac{1}{6}(0.7)=0.117 m$

7 0

3 years ago

Question 3 (1 point)

FrozenT [24]

The force of friction is equal to the pushing force, and the acceleration is zero

Explanation:

In this problem, we are pushing a piano along the floor, in the horizontal direction.

There are 2 forces acting in the horizontal direction on the piano:

The applied force, $F_a$ , acting forward
The force of friction, $F_f$ , acting backward

Therefore, the net force in the horizontal direction is

$\sum F = F_a - F_f$

According to Newton's second law, the net force is equal to the product between the piano's mass (m) and its acceleration:

$\sum F = ma$

Combining the two equations,

$F_a - F_f = ma$

However, we are also told that the piano moves at constant speed, therefore the acceleration is zero:

$a=0$

And so,

$F_a - F_f = 0\\F_f = F_a$

which means that the force of friction is equal to the applied force.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

3 0

3 years ago