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Olegator [25]
3 years ago
6

Select the expression equal to square root of 24

Mathematics
1 answer:
enyata [817]3 years ago
8 0

<em>look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

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If you know the number of yards for a measurement, you can change that measure to
otez555 [7]

Answer:

f(x) = 0.9144x

Step-by-step explanation:

To convert 3 yards to meters by multiplying 3*0.9144 = 2.7432 meters. This can be done for any number of yards x by writing f(x) = 0.9144x.

7 0
4 years ago
Which statement is true? 7.1G
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In the 7th grade, 132 students take Spanish as an elective. If there are 330 seventh graders, what percent of
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Step-by-step explanation: 40% 132/330=0.4 and 0.4 as a percent is 40%

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What is the value of 7P4?<br> 144<br> 35<br> 28<br> 840
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Answer: The value of 7P4 is 28

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3 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
3 years ago
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