<span>it says that all particles of matter are in constant motion </span>
Answer:
A person can identify their blood type at home using a rapid blood typing kit. Using the kit requires a person to pierce a finger with a needle. The kit comes with a card that contains chemicals known as reagents. These test for the presence of the antibodies and Rh factor.
Explanation:
Just like eye or hair color, our blood type is inherited from our parents. Each biological parent donates one of two ABO genes to their child. The A and B genes are dominant and the O gene is recessive. For example, if an O gene is paired with an A gene, the blood type will be A.
<u>Answer:</u>
<em>Two atoms of the same element are most likely to form Molecule.</em>
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<u>Explanation:</u>
are some examples
1 molecule of fluorine contains 2 atoms of Fluorine.
Similarly,
One molecule of chlorine (Cl),
One molecule of bromine (Br),
One molecule of iodine (I)
Each contains two atoms of the same element. We call these molecules as homodiatomic molecules.
There are 7 diatomic molecules which are as follows,
They are
and ![H_2](https://tex.z-dn.net/?f=H_2)
Answer:
![\boxed{\text{53 g }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B53%20g%20%7D%7D)
Explanation:
You don't give the reaction, but we can get by just by balancing atoms of Na.
We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
M_r: 142.04
2NaOH + … ⟶ Na₂SO₄ + …
n/mol: 0.75
1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.
Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH
= 0.375 mol Na₂SO₄
2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.
Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄
The reaction produces
of Na₂SO₄.
Answer:
120 moles of Mg
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
3Mg + 2H₃PO₄ —> Mg₃(PO₄)₂ + 3H₂
From the balanced equation above,
3 moles of Mg reacted to produce 3 moles of H₂.
Finally, we shall determine the number of mole of Mg needed to produce 120 moles of H₂. This can be obtained as follow:
From the balanced equation above,
3 moles of Mg reacted to produce 3 moles of H₂.
Therefore, 120 moles of Mg will also react to produce 120 moles of H₂.
Thus, 120 moles of Mg is needed for the reaction.