Answer:
5
Explanation:
Firstly, we convert what we have to percentage compositions.
There are two parts in the molecule, the sulphate part and the water part.
The percentage compositions is as follows:
Sulphate- (103.74)/(103.74 + 58.55) × 100% = apprx 64%
The water part = 100 - 64 = 36%
Now, we divide the percentages by the molar masses.
For the CuSO4 molar mass is 64 + 32 + 4(16) = 160g/mol
For the H2O = 2(1) + 16 = 18g/mol
Now we divide the percentages by these masses
Sulphate = 64/160 = 0.4
Water = 36/18 = 2
The ratio is thus 0.4:2 = 1:5
Hence, there are 5 water molecules.
electrons are transferred in a oxidation-reduction reaction
oxidation reduction chemical equation involve electrons transfer between two species. In this reduction-oxidation type of chemical equation oxidation number of molecule, atoms or ion changes by gaining or losing electrons,that is there an oxidizing agent and a reducing agent in the reaction.
68.7g
molar mass of Ba(137.327)x (.500)= 68.6635
.500 has 3 sig figs.
Answer:
ΔG < 0
Explanation:
The condition for spontaneity of a chemical reaction is that ∆G<0. Hence for any biochemical reaction to proceed as written, ∆G must have a negative value.
If ∆G >0, the reaction is not spontaneous and will not proceed as written. ∆G=0 means that the reaction has attained equilibrium.
