<h3><u>Answer</u>;</h3>
≈ 4.95 g/L
<h3><u>Explanation;</u></h3>
The molar mass of KCl = 74.5 g/mole
Therefore; 0.140 moles will be equivalent to ;
= 0.140 moles × 74.5 g/mole
= 10.43 g
Concentration in g/L
= mass in g/volume in L
= 10.43/2.1
= 4.9667
<h3> <u> ≈ 4.95 g/L</u></h3>
There are 4 atoms of sodium in the formula of sodium sulfite.
<h3 /><h3>Number of atoms at sodium</h3>
There are 4 atoms of sodium in the formula of sodium sulfite because 4 digit is placed before sodium which shows the number of sodium atom present in the molecule while on the other hand, 2 is placed in front of sulfur which tells us that 2 atoms of sulfur is used in the making of sodium sulfite.
<h3>Reasons of war</h3>
In this excerpt, Paine is attempting to convince the readers that we have righteous reasons to justify supporting the war. We should participate and take part in the war in order to defend ourselves and our country but avoid offensive war to gain financial benefits.
Learn more about war here: brainly.com/question/1174232
Learn more: brainly.com/question/26123703
Answer:
140 grams
Explanation:
.14 kilograms to grams is <em>140</em><em> </em><em>grams</em><em> </em>
<em>PLEASE DO</em><em> </em><em>MARK ME</em><em> </em><em>AS BRAINLIEST</em><em> </em><em>UWU</em><em> </em>
The reaction that should be followed is
Na2SO4 + C<span>a(NO3)2 --> CaSO4 + 2NaNO3</span>
first calculate the limiting reactant
mol Na2SO4 = 0.075 L (<span>1.54×10−2 mol / L) = 1.155x10-3 mol
mol Ca(NO3)2 = 0.075 L (</span><span>1.22×10−2 mol / L) = 9.15x10-4 mol
so the limiting reactant is the Ca(NO3)2
so all of the Ca2+ will be precipitated, percentage unprecipitated = 0.00 % </span>
