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Varvara68 [4.7K]
3 years ago
15

9. How do airbags protect the occupants of a car in a crash? Use the following words in

Chemistry
1 answer:
pentagon [3]3 years ago
5 0
\textbf{Answer:}

Airbags are good for car crashes and have saved lots of life’s, the force of the airbags are dangerous though because they come out with fast acceleration and when it is hot it can burn you. If there is ever a time for collision airbags may save your live!

- ( I would appreciate if you gave brainliest if I helped you, if not please let me know what I got wrong! If you need any more help do not hesitate to ask! :) )

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Alchemy was practiced _____.
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The answer is c maybe
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The specific heat of aluminum is s 9.00 J/g C how much energy is needed to raise the temperature of 20.0 g block of aluminum fro
Nimfa-mama [501]
E=MC(delta)T
=20.0g x 9.00J/g x (94.4-22.8) C
= 12,924.0 J
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Match the term with the definition.
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C4H10 is an example of a (n) a. Molecular formula b. Structural formula c. Atomic formula d. Geometric formula​
Oxana [17]

Answer:

molecular formula

Explanation:

hope it helps

8 0
3 years ago
Select the correct answer from each drop-down menu.
earnstyle [38]

Answer:

The granite block transferred <u>4080 joules</u> of energy, and the mass of the water is <u>35.84 grams</u>.

Explanation:

The equation needed to answer both parts of the question is:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

<u>Part #1:</u>

First, you need to find the energy transferred from granite block using the previous equation. You have been given the mass, specific heat, and change in temperature.

Q = ? J                            c = 0.795 J/g°C

m = 126.1 g                     ΔT = 92.6 °C - 51.9 °C = 40.7 °C

Q = mcΔT

Q = (126.1 g)(0.795 J/g°C)(40.7 )

Q = 4080

<u>Part #2:</u>

Secondly, using the energy calculated in Part #1, you need to calculate the mass of the water. You have calculated the energy transferred, and have been given the specific heat and change in temperature.

Q = 4080 J                     c = 4.186 J/g°C

m = ? g                            ΔT = 51.9 °C - 24.7 °C = 27.2 °C

Q = mcΔT

4080 J = m(4.186 J/g°C)(27.2 °C)

4080 J = m(113.8592)

35.84 = m

4 0
2 years ago
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