Answer:
volume of
Explanation:
Firstly balance the given chemical equation,
From the given balance equation it is clearly that,
2 mole of Li gives 1 mole of H2 gas
⇔
⇔
⇔
hence
3 mole of Li will give 1.5 mole H2 gas
therefore volume of gas produced from 3 mole Li at
volume of H2=33.6 litre
Given the balanced chemical equation for combustion of propane:
Moles of propane =3.6 mol
Propane is the limiting reactant as the other reactant oxygen is said to be present in excess.
Amount of products formed would depend on the moles of limiting reactant.
Mole ratio of water to propane as per the balanced chemical equation
=
Calculating the moles of water produced from 3.6 mol propane:
= 14.4mol
Theoretical yield of water = 14.4 mol
Actual yield = 12 mol
Percent yield =
=