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I am Lyosha [343]
2 years ago
5

Which statements best describe half-lives of radioactive isotopes? Check all that apply.

Chemistry
2 answers:
AURORKA [14]2 years ago
5 0

Answer: The half-life varies depending on the isotope.  Half-lives range from fractions of a second to billions of years.   The half-life of a particular isotope is constant.  

Explanation: On Edgenuity!!!!

Igoryamba2 years ago
3 0

Answer:

The half-life varies depending on the isotope.

Half-lives range from fractions of a second to billions of years.

The half-life of a particular isotope is constant.

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If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be
Korvikt [17]

Answer:30 L

Explanation:

Initial Volume

=

V

1

=

60

l

i

t

e

r

Initial Temperature

=

T

1

=

546

K

Final Temperature

=

T

2

=

273

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Final Vloume

=

V

2

=

?

?

Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,

V

1

T

1

=

V

2

T

2

⇒

V

2

=

V

1

⋅

T

2

T

1

=

60

⋅

273

546

=

60

2

=

30

l

i

t

e

r

⇒

V

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=

30

l

i

t

e

r

Hence the new volume of the gas is

30

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e

r

6 0
3 years ago
Identical wire loops are dipped into Liquid X and Liquid Y, so that a film of liquid forms across the loops (like the bubble sol
muminat

Answer:

a.

Explanation:

Assuming that Liquid X is considered to possess a greater viscosity as well as higher surface tension than liquid Y. Then, liquid X will tend to harbour more pressure inside the liquid.

In addition to that, the greater the surface tension, the greater the force required to expand the liquid's surface area.

This in turn makes the force required to make the loop 5% wider to be greater in FX rather than FY.

Thus, option a is the correct answer.

6 0
2 years ago
What is the study of nature and the physical world using the scientific method
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The correct answer is 30 seconds

6 0
3 years ago
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zimovet [89]
The balanced chemical equation would be as follows:

<span>K2PtCl4(aq) + 2NH3(aq) --> Pt(NH3)2Cl2(s) + 2KCl(aq)

We are given the amount of </span>K2PtCl4 to be used in the reaction. This will be the starting point for our calculations. We do as follows:

65 g K2PtCl4 ( 1 mol / 415.09 g ) ( 1 mol Pt(NH3)2Cl2 / 1 mol K2PtCl ) ( 300.051 g / 1 mol ) = 46.99 g Pt(NH3)2Cl produced 
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3 years ago
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