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3 years ago

14

If you were sitting near a gram of protactinium-234 and a gram of uranium-234, both solid materials, which would you consider mo

re dangerous to you?

1 answer:

Novosadov [1.4K]3 years ago

6 0

aswer: protactinium-234 is more dang erous than uranium

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What is the molarity of a solution with a volume of 974 mL containing 17 g of CuSO4

liberstina [14]

Answer : The correct option is, (A) 0.109 M $CuSO_4$

Solution : Given,

Mass of $CuSO_4$ = 17 g

volume of solution = 974 ml

Molar mass of $CuSO_4$ = 159.609 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{w\times 1000}{M\times V_s}$

where,

w = mass of $CuSO_4$ (solute)

M = molar mass of $CuSO_4$

$V_s$ = volume of solution in liter

Now put all the given values in the above formula, we get the molarity of solution.

$Molarity=\frac{(17g)\times 1000}{(159.609g/mole)\times (974ml)}=0.109mole/L=0.109M$

Therefore, the molarity of the solution is, 0.109 M

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4 years ago

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What is a single celled orginium able to do

vichka [17]

<span>Many life forms consist of a single cell. As well as simple bacteria, there are more complex organisms, known as protoctists. Unlike bacteria, they have complex internal structures, such as nuclei containing organized strands of genetic material called chromosomes. Most are single-celled, but some form colonies, with each cell usually remaining self-sufficient.</span>

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3 years ago

Identify the reaction type of the chemical reaction below. Check all that apply.

Ilya [14]

Answer:

The type of reaction is a single-replacement reaction.

Explanation:

Mg switches places with H, leaving H by itself.

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3 years ago

Describe bonding in water molecules using the VBT. Show the overlap of hybridised orbitals leading to the formation of H2O molec

Bogdan [553]

Yes I’m going to go ask my mama, she said the answer is 1993629

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3 years ago

Consider the reaction: A (aq) ⇌ B (aq) at 253 K where the initial concentration of A = 1.00 M and the initial concentration of B

Ugo [173]

Answer:

The maximum amount of work that can be done by this system is -2.71 kJ/mol

Explanation:

Maximum amount of work denoted change in gibbs free energy $(\Delta G)$ during the reaction.

Equilibrium concentration of B = 0.357 M

So equilibrium concentration of A = (1-0.357) M = 0.643 M

So equilibrium constant at 253 K, $K_{eq}= \frac{[B]}{[A]}$

[A] and [B] represent equilibrium concentrations

$K_{eq}=\frac{0.357}{0.643}=0.555$

When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M

So reaction quotient at this situation, $Q=\frac{0.133}{0.867}=0.153$

We know, $\Delta G=RTln(\frac{Q}{K_{eq}})$

where R is gas constant and T is temperature in kelvin

Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and $K_{eq}$ is 0.555

So, $\Delta G=8.314\times 253\times ln(\frac{0.153}{0.555})mol/K$

= -2710 J/mol

= -2.71 kJ/mol

4 0

3 years ago