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3 years ago

4. What happens when a bond is formed between a greenish yellow gaseous element X and a

Chemistry

2 answers:

weeeeeb [17]3 years ago

6 0

Answer:

A. Atom x gains an electron

Explanation:

What happens when a bond is formed between a green gaseous element and a soft metallic element?（2.0分）

A. The gas atoms gain an electron.

B. The gas atoms lose an electron.

C. The metal atoms gain an electron.

D. The two elements share a pair of electrons

charle [14.2K]3 years ago

4 0

Answer:

A). Atom x gains an electron.

hope this is right answer.

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A student mixes 33.0 mL of 2.70 M Pb ( NO 3 ) 2 ( aq ) with 20.0 mL of 0.00157 M NaI ( aq ) . How many moles of PbI 2 ( s ) prec

GalinKa [24]

Answer: The moles of precipitate (lead (II) iodide) produced is $1.57\times 10^{-5}$ moles

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

For lead (II) nitrate:

Molarity of lead (II) nitrate solution = 2.70 M

Volume of solution = 33.0 mL = 0.033 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$2.70M=\frac{\text{Moles of lead (II) nitrate}}{0.033L}\\\\\text{Moles of lead (II) nitrate}=(2.70mol/L\times 0.0330L)=0.0891mol$

For NaI:

Molarity of NaI solution = 0.00157 M

Volume of solution = 20.0 mL = 0.020 L

Putting values in equation 1, we get:

$0.00157M=\frac{\text{Moles of NaI}}{0.020L}\\\\\text{Moles of NaI}=(0.00157mol/L\times 0.0200L)=3.14\times 10^{-5}mol$

For the given chemical reaction:

$Pb(NO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaNO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts with 1 mole of lead (II) nitrate

So, $3.14\times 10^{-5}$ moles of NaI will react with = $\frac{1}{2}\times 3.14\times 10^{-5}=1.57\times 10^{-5}mol$ of lead (II) nitrate

As, given amount of lead (II) nitrate is more than the required amount. So, it is considered as an excess reagent.

Thus, NaI is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, $3.14\times 10^{-5}$ moles of NaI will produce = $\frac{1}{2}\times 3.14\times 10^{-5}=1.57\times 10^{-5}moles$ of lead (II) iodide

Hence, the moles of precipitate (lead (II) iodide) produced is $1.57\times 10^{-5}$ moles

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3 years ago

Which statement is true about crystal lattice energy

Arturiano [62]

Hey there!:

1) The additional stability that accompanies the formation of the networkCrystalline is measured as network enthalpy.
2) The reticular energy is the energy released when the solid Crystal isform from separate ions in the gaseous state. Always exothermic.
3) The enthalpy of the network depends directly on the size of the loads and conversely in the distance between the ions .

hope this helps!

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3 years ago

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0.65743 In scientific notation

Goryan [66]

202827.0000 is the answer I think idrk

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3 years ago

What tool did scientist use to first study the Earth’s interior

IgorC [24]

Seismic waves hope this helps.

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3 years ago

Given the chemical formulas of the following compounds, name each compound and state the rules you used to determine each name.

Svetlanka [38]

When naming an ionic compound, write the name of the cation, which is the metal first. Then, write the name of the anion, which is the nonmetal. However, you remove the last 2-3 letters and replace suffixes.

1. RbF --> Rubidium Fluoride
Change fluorine to fluoride
2. CuO --> Copper (II) Oxide
Change oxygen to oxide. Oxide has a charge of -2. Since no subscripts are written, it means they have the same opposite charge. So, we use Copper (II).
3. (NH₄)₂C₂O₄ ---> Ammonium Oxalate
NH₄ is ammonia, but we change it to ammonium for polyatomic ions.

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3 years ago