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neonofarm [45]
2 years ago
13

The tile pattern below is made up of trapezoids and rhombuses. What is the area of each figure in the pattern?

Mathematics
1 answer:
shutvik [7]2 years ago
6 0

The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively

<h3>How to find the area of a trapezoid and rhombus?</h3>

The given pattern consists of rhombus and trapezoids

The formula for calculating the area of rhombus is expressed as:

A = pq/2

Area of trapezoid = 0.5(a+b)h

Given the following

height  = 2in

a = 2in

b = 3in

Ara of rhombus = 1(4)/2 = 2 square inches

Area of the trapezoid = 0.5(2+3) * 2

Area of the trapezoid  = 5 square inches

Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively

Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096

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The length of a side of a triangle is 36. A line parallel to that side divides the triangle into two parts of equal area. Find t
sp2606 [1]

Answer:

Length of DE is : 18√2 units

Step-by-step explanation:

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\implies Area(ADE)=\frac{1}{2}\times Area(ABC) \\\\\implies \frac{Ar(ADE)}{Ar(ABC)}=\frac{1}{2}

In ΔABE and ΔABC,

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By AA postulate of similarity of triangles, ΔABE ~ ΔABC.

Hence by area side proportionality theorem

\frac{Ar(ADE)}{Ar(ABC)}=(\frac{DE}{BC})^2\\\\\implies \frac{1}{2}=\frac{DE^2}{36^2}\\\\\implies DE^2=\frac{36^2}{2}\\\\\bf\implies DE=18\sqrt{2}\textbf{ units}

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Step-by-step explanation:

i hope its help

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