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Volgvan
2 years ago
8

1 gallon = 3.8 liters 1 mile = 1.6 kilometers using the conversion above,a bus that uses that uses 10 liters of gasoline to trav

el 10 liters of gasoline to travel 100 kilometers would have an efficiency rating closest to a) 15 miles per gallon b) 24 miles per gallon c) 38 miles per gallon d) 60 miles per gallon
Mathematics
1 answer:
zheka24 [161]2 years ago
5 0

9514 1404 393

Answer:

  b) 24 miles per gallon

Step-by-step explanation:

The usual metric measure of vehicle fuel efficiency is liters per 100 km. Greater efficiency is indicated by a lower value.

In the US, the measure is usually miles per gallon. Greater efficiency is indicated by a higher value. Since we want the efficiency expressed in miles per gallon, we need to divide distance by fuel consumption.

  (distance)/(fuel used) = (100 km)/(10 L)

  = (100 km)/(10 L) × (1 mi)/(1.6 km) × (3.8 L)/(1 gal) = (100×3.8)/(10×1.6) mi/gal

  = 23.75 mi/gal ≈ 24 mi/gal

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One T-shirt is sold for every 5 people who attend a concert. What is one way to write the unit rate in words?
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Answer : the answer is 5 people per T-shirt

Step-by-step explanation: because its 5 people per 1 T-shirt

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3 years ago
You are hosting a convention for a charitable organization. You pay a rental fee of $28,500 for the convention center, plus you
Alexxandr [17]
You have to add the $51 to $13 and find the answer then divide the sum by $28,500
8 0
3 years ago
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Choose the graph that represents the following system of inequalities:
Licemer1 [7]

Answer:

FIRST.

64 square inches matches to a cross section parallel to the base of a right rectangle prism that is 3 inches long, 7 inches wide, and 11 inches tall

This is shown in the first figure below. A right rectangular prism where every edge connecting its base and the opposite face makes right angles with both faces. Since the tall is the side that measures 11 inches, then the base is formed by 3 inches long and 7 inches wide. Therefore, the area of this shape can be found as the area of a rectangle, which is: 21 in squared.

SECOND.

64 square inches matches to a cross section parallel to the base of a cube whose edges are 8 inches long.

This is shown in the second figure below. A cube is a prism whose sides all have the same length and in this case is 8 inches. We name cross section is to the slice that cuts through a solid. If the cross section is parallel to the base of a cube, then it forms a square with length . Therefore, the area of this shape can be found as the area of a square, which is: 64 in squared.

Third.

7 square inches matches to a cross section passing through the diagonal of opposite faces of a cube with edges that are 7 inches long and a diagonal that is approximately 10 inches

This is shown in the third figure below. As you can see, the cross section passes through the diagonals of the base and the top of the cube that are two opposite faces. This form a rectangle having sides  where:

So: 70 in squared

FOURTH.

300 square inches matches to a cross section perpendicular to the base and passing through the diagonals of the base and opposite face of a right rectangular prism that is 24 inches wide, 7 inches long, and 12 inches tall and measures 25 inches along the diagonal of the base.

This is shown in the fourth figure below. The cross section passes through the diagonals of the base and the top of the right rectangular prism. They are opposite to each other, so the shape of the cross section is a rectangle whose sides are  where:

So: 300 in squared.

Step-by-step explanation:

6 0
3 years ago
Solve |t+4| > 10
diamong [38]
For
|a|>b
assume
a>b and a<-b

|t+4|>10
assume
t+4>10 and t+4<-10
solve each
minus 4 both sides

t>6 and t<-14


A is answer

7 0
3 years ago
Solve by substitution or elimination 5x+3y=-15 -8x-2y=10
Cerrena [4.2K]

Answer:

x=0, y=-5

Step-by-step explanation:

The system is

(1)  5x+3y=-15  

(2) -8x-2y=10

Let's solve it by elimination.  In order to do it, you have to multiply the equations by suitable numbers in such a way that when you add the 2 equations, one of the unknowns is eliminated

Multiply (1) by 2 and (2) by 3

(1) 10x+6y=-30

(2) -24x-6y=30

Add the two equations

10x-24x+6y-6y=-30+30 ----> -14x=0---->x=0

Now replace this value in any equation, for example in (1)

6y=-30 ----> y=-30/6----> y=-5

5 0
3 years ago
Read 2 more answers
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