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3 years ago

13

A square root of 54

4 \sqrt{3 } " alt=" \\ 54 \sqrt{3 } " align="absmiddle" class="latex-formula">

1 answer:

11111nata11111 [884]3 years ago

8 0

What’s the question?

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Helpppppppppp please

eduard

You know b=-6 and since you know this, you can plug -6 in for b.

This would become 4(-6) + 6 divided by 6.

You can then multiply 4 and -6 together,

-24 + 6 / 6

You can then add -24 and 6 together,

-18/6

You can then divide -18 by 6,

-18/6=-3

-3 is your final answer

7 0

4 years ago

Read 2 more answers

A plane flying overhead at night is located by two

Gemiola [76]

Answer:

Step-by-step explanation:

B

2

3

Let the distance of two consecutive stones are x, x+1.

In ΔBCD, we have

tan60

o

=

x

h

⇒x=

3

h

.....(i)

In ΔABC, we have

tan30

o

=

x+1

h

⇒

3

1

=

x+1

h

⇒

3

h

+1=

3

h ......[from equation (i)]

⇒

3

2h

=1

⇒h=

2

3

km

solution

6 0

3 years ago

5. Amy deposited $7,000 in a bank account earning 3.5% interest, compounded

Semenov [28]

Answer:

Step-by-step explanation:

Given the following data;

Principal = $7,000

Interest = 3.5% = 3.5/100 = 0.035

To find the future value, we would use the compound interest formula;

$A = P(1 + \frac{r}{n})^{nt}$

Where;

A is the future value.

P is the principal or starting amount.

r is annual interest rate.

n is the number of times the interest is compounded in a year.

t is the number of years for the compound interest.

Substituting into the equation, we have;

$A = 7000(1 + \frac{0.035}{n})^{nt}$

7 0

3 years ago

I need the angle of elevation

Aleksandr-060686 [28]

Answer:

multiply and see what you get

4 0

3 years ago

Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti

almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

$d=v.t$

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

$d=(x+y).t_1$

Where t1=2.5 hours. Substituting values:

$20=(x+y)*2.5$

Rearranging, we find the downstream equation:

$2.5x+2.5y=20\qquad[1]$

The speed when rowing upstream is x-y, and the distance traveled is

$d=(x-y).t_2$

Where t2=5 hours. Substituting values:

$20=(x-y)*5$

Rearranging, we find the upstream equation:

$5x-5y=20\qquad[2]$

Multiplying [1] by 2:

$5x+5y=40$

Adding this equation to [2]:

$10x=60$

Solving:

$x=60/10=6$

Dividing [2] by 5:

$x-y=4$

Solving for y

$y=x-4=6-4=2$

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0

4 years ago