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2 years ago

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A square root of 54

4 \sqrt{3 } " alt=" \\ 54 \sqrt{3 } " align="absmiddle" class="latex-formula">

1 answer:

11111nata11111 [884]2 years ago

8 0

What’s the question?

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Base your answer on Betty is thinking of two consecutive integers whose sum is 41.

mel-nik [20]

Answer:

let the numbers be, x and x+1 ( as it is consecutive number the next number will have 1 more than the number )

sum = 41

so, x + ( x + 1 ) = 41

x + x + 1 = 41

2x + 1 = 41

2x = 41 -1 = 40

2x = 40

x = 40/2 = 20

x = 20

x + 1 = 20 + 1 = 21

so the consecutive numbers whose sum is 40 are, 20 and 21

hope this answer helps you.....

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3 years ago

1. Mr. Davis deposited $1,250 into an account. He made no additional deposits or

cluponka [151]

Answer:mn jjjjjjjjjjjjjjjjjjjjjjjj,uyhhhbgfvStep-by-step explanation:

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3 years ago

Belize is a small country in Central America. The

shepuryov [24]

Answer:

60 inches

Step-by-step explanation:

<em>30% of 200 inches = 200 inches * 30%</em>

<em>30% = 0.3</em>

Substitute: 200 inches * 0.3

Multiply: 60 inches

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3 years ago

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3 years ago

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Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type

Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

$\frac{y}{t} = e^{-kt + C} \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt} (A = e^{C})\\y = Ate^{-kt}$

when t = 1 hour, y = 15 grams. So,

$y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}$ (1)

when t = 3 hours, y = 30 grams. So,

$y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k}$ (2)

dividing (2) by (1), we have

$\frac{30}{15} = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}$

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

$A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36$

Substituting A and k into y, we have

$y = 18.36te^{-0.203t}$

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

$y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g$

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

3 0

3 years ago