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xz_007 [3.2K]
3 years ago
14

Please help me figure out this problem

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

f(g(x))=f\left(-\dfrac{3x+21}{5}\right)=x\\\\g(f(x))=g\left(-\dfrac{5}{3}x-7\right)=x

Step-by-step explanation:

Fill in the given expressions and simplify.

f(g(x))=f\left(-\dfrac{3x+21}{5}\right)=-\dfrac{5}{3}\left(-\dfrac{3x+21}{5}\right)-7\\\\=\left(-\dfrac{5}{3}\right)\left(-\dfrac{3x}{5}\right)-\left(\dfrac{5}{3}\right)\left(-\dfrac{21}{5}\right)-7\\\\=\dfrac{15x}{15}+\dfrac{5\cdot 21}{3\cdot 5}-7=x+7-7=x

Going the other way, we have ...

g(f(x))=\displaystyle -\frac{3\left(-\frac{5}{3}x-7\right)+21}{5}=-\frac{-5x-21+21}{5}=x

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Answer:

If it is horizontal then it is zero, if it is vertical then it is undefined

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3 years ago
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Tems11 [23]

Answer:

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Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

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On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

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R(12) = 2ln13 + 2√13

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Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

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When t = 24

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2 years ago
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