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DedPeter [7]
3 years ago
15

Solve the equation: [3255] [x1 x2] + [1 2] = [2 -3]​

Mathematics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer: x=-13/6510

Step-by-step explanation:

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Help meeeeeeeeeee I need help please please please please please please please please please please please
Kamila [148]
Its 1 = 5 im pretty sure
6 0
4 years ago
Two cities A and B are 1400km apart and lie on the same N-S line. The latitude of city A is 23 Degrees. What is the latitude of
erica [24]

Answer:

{\theta}=12.53 degrees≈13degrees

Step-by-step explanation:

It is given that Two cities A and B are 1400km apart and lie on the same N-S line. The latitude of city A is 23 Degrees. Then,

Using the formula, S=r{\theta} where s is the distance between the two cities and r is the radius of the earth,thus substituting the values, we get

1400=6400{\theta}

⇒{\theta}=\frac{14}{64}

Therefore, {\theta}=\frac{14}{64}{\times}\frac{180^{{\circ}}}{{\pi}}

⇒{\theta}=\frac{2520}{200.96}

⇒{\theta}=12.53 degrees

Thus, the latitude of B is=12.53 degrees≈13degrees

4 0
4 years ago
Roberto tiene 20 balones entre azules y rojos el tiene mas balones rojo que azules y los guarda en cuatro bolsas que contienen l
Anuta_ua [19.1K]

Se pueden concluir dos posibilidades para cada bolsa y toda la colección:

  1. 4 balones rojos y un balón azul, lo cual lleva a 16 balones rojos y 4 balones azules.
  2. 3 balones rojos y dos balones azules, lo cual lleva a 12 balones rojos y 8 balones azules.

<h3>¿Cuántos balones rojos tiene Roberto en las cuatro bolsas?</h3>

En este problema conocemos que Roberto tiene 20 balones entre azules y rojos y que existen más balones rojos que azules. Puesto que los balones son objetos que pueden contarse, los datos a buscar deben ser números enteros y positivos y que están distribuidos equitativamente en cuatro bolsas. Entonces las cantidades de balones por bolsa son:

x = 20 / 4

x = 5

Existen 5 balones por bolsa y bajo la consideración de que existen balones azules, que cada bolsa tienen la misma proporción de balones rojos a azules y que los balones rojos son más que los balones azules, se pueden concluir dos posibilidades para cada bolsa:

  1. 4 balones rojos y un balón azul, lo cual lleva a 16 balones rojos y 4 balones azules.
  2. 3 balones rojos y dos balones azules, lo cual lleva a 12 balones rojos y 8 balones azules.

Para aprender más sobre proporciones: brainly.com/question/27957192

#SPJ1

7 0
2 years ago
Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar
xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ_{e}^2 → S_{e} ^{2}), you have to use the following formula:

Se²=<u> (n₁-1)S₁² + -(n₂-1)S₂² + (n₃-1)S₃²</u>

                        n₁+n₂+n₃-k

Se²=<u> 19*14.3 + 19*17.2 + 19*16.7 </u>= <u>  915.8   </u>  = 16.067

                 20+20+20-3                  57

DfE= N-k = 60-3= 57

3. To calculate the value of the statistic you have to divide the MSB by MSE

F= \frac{Mean square B}{Mean square E} = \frac{5.32}{16.067} = 0.33

4. P(F_{2; 57} ≤ F) = P(F_{2; 57} ≤ 0.33) = 0.28

I hope you have a SUPER day!

3 0
3 years ago
How many extraneous solutions exist for the logarithmic equation below if it is solved in the most efficient way possible?log_(2
Nadusha1986 [10]

Answer:

No extraneous solution

Step-by-step explanation:

We have the logarithmic equation given by,

\log_{2}[\log_{2}(\sqrt{4x})]=1

i.e. \log_{2}(\sqrt{4x})=2^{1}

i.e. \sqrt{4x}=2^{2}

i.e. \sqrt{4x}=4

i.e. 4x=4^{2}

i.e. 4x=16

i.e. x=4

So, the solution of the given equation is x=4.

Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is ( 0,\infty ).

Therefore, the domain of the given function is x > 0.

We know that the extraneous solution is the solution which does  not belong to the domain.

But as x=4 belongs to the domain x > 0.

Thus, x = 4 is not an extraneous solution.

Hence, this equation does not have any extraneous solution.

7 0
3 years ago
Read 2 more answers
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