All categories

3 years ago

I need help with this question from study island

Mathematics

2 answers:

dem82 [27]3 years ago

8 0

It is the Rainy question

Hunter-Best [27]3 years ago

5 0

Actually is the Monica one

You might be interested in

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$

Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

$\dfrac{\sin(x)}{\cos(x)} = \tan(x)$

Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

Hence, it is proved

5 0

3 years ago

Prove the polynomial identity. (2x−1)2+2(2x−1)=(2x+1)(2x−1) Drag and drop the expressions to correctly complete the proof of the

Alex_Xolod [135]

Answer:

Step-by-step explanation:

Given expression is,

(2x - 1)² + 2(2x - 1) = (2x - 1)(2x + 1)

To prove this identity we will take the left hand side of the equation and will prove equal to the right side.

(2x - 1)² + 2(2x - 1) = (2x - 1)(2x + 1)

4x² - 4x + 1 + 4x - 2 = (2x - 1)(2x + 1)

4x² - 1 = (2x - 1)(2x + 1)

(2x - 1)(2x + 1) = (2x - 1)(2x + 1) [Since a² - b² = (a - b)(a + b)]

6 0

4 years ago

Please help me with this

AfilCa [17]

Answer:

A. 4/5

Step-by-step explanation:

The red dot is on 0.8

0.8 as a fraction is 4/5

8 0

3 years ago

Read 2 more answers

Write a linear function f with f(−10)=4 and f(−2)=4.

Orlov [11]

f(-10) = 4

f(-2) = 4

Since y is constant while x isnt we just dont need to put x

f(x) = 4

6 0

4 years ago

Lol here it attached this timeline give brainliest

ra1l [238]

Answer:

Step-by-step explanation:

x-5=42

x=42+5

x=47

5 0

3 years ago

Read 2 more answers