Shane worked 8 hours per day for 3 days. Andrew worked 6 hours per day for 4 days. If the normal working week is 36 hours, which
2 answers:
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Let's say hmm let's use the figures in thousands, so
model A costs 90 + 4 per year, so... ok.. after "t" years, then the cost for model A is then 90 + 4*t, or A = 90 + 4t.
now, model B is 70 + 10 per year, so,... after "t" years, model B is then
B = 70 + 10 * t, or B = 70 + 10t.
if we were to assume A < B, namely the cost of A is less than B, what would the years be? namely, what's "t"?
after that period, then A becomes cheaper than B.
model A costs 90 + 4 per year, so... ok.. after "t" years, then the cost for model A is then 90 + 4*t, or A = 90 + 4t.
now, model B is 70 + 10 per year, so,... after "t" years, model B is then
B = 70 + 10 * t, or B = 70 + 10t.
if we were to assume A < B, namely the cost of A is less than B, what would the years be? namely, what's "t"?
after that period, then A becomes cheaper than B.
Answer:
Step-by-step explanation:
*Move terms to the left and set equal to zero:
4㏒(√x) - ㏒(3x) - ㏒(x²) = 0
*simplify each term:
㏒(x²) - ㏒(3x) - ㏒(x²)
㏒(x²÷x²) -㏒(3x)
㏒(x²÷x² / 3x)
*cancel common factor x²:
㏒()
*rewrite to solve for x :
10⁰ =
1 =
1 · x = · x
1x =
*that would be our answer, however, the convention is to exclude the "1" in front of variables so we are left with:
x =
Use sine inverse since you have the lengths of both the hypothenuse and opposite of the triangle formed:)
