The slope of the line is 4
The point slope form of the line can be written as (y - 8) = 4(x - 9)
The slope intercept form of the line is y = 4x - 28
In order to find the slope you will need to use the formula for slope. It is included below.
m(slope) = (y2 - y1)/(x2 - x1)
m = (8 - -12)/(9 - 4)
m = (8 + 12)/(9 - 4)
m = 20/5
m = 4
Now that we have the slope, we can plug it into point slope form along with one of the points.
(y - y1) = m(x - x1)
(y - 8) = 4(x - 9)
Now to get to the slope-intercept form of the line, we can simply manipulate the point-slope form until it is in y = mx + b
(y - 8) = 4(x - 9) ----> Distribute the 4
y - 8 = 4x - 36 -----> Add 8 to both sides
y = 4x - 28
X = 4(cosθ - cos²θ) = 4cosθ - 4cos²<span>θ
</span>dx/dθ = -4sinθ + 8sinθcosθ = -4sinθ(1 - 2cos<span>θ)
dy/d</span>θ = 4(cosθ - cos²θ + sin²θ) = 4(cos<span>θ - 1)
</span>∴dy/dx = 4(cosθ - 1)/-4sinθ(1 - 2cosθ) = 1-cosθ/(sinθ - 2sinθcosθ<span>)
Now, we're finding a horizontal tangent, which is when dy/dx = 0 (horizontal tangent).
1-cos</span>θ/(sinθ - 2sinθcosθ) = 0
1-cosθ = 0
cosθ = 1
θ = 0, 360 in the interval [0, 360].
At θ = 0, x = 0, y = 0
Only points in the open interval [-2π, 2π] are at (0, 0), unless I made a mistake somewhere.
Answer:
im broke so i robbed u
Step-by-step explanation:
Answer:
8 weeks
Step-by-step explanation:
$2100 - $900 = $1200
$1200/$150 = 8 weeks