You are a truck driver for a distribution center. You drove 30 hours in 5 days. What is your per day average?

WILL GIVE BRAINLIST ANSWERS

enot [183]

Answer:

-10

-I-8I = -8

-(-2) = 4

I-11I = 11

5² = 25

Answer: -10, -8, 4, 11, 25

6 0

2 years ago

There are 112 seats in the school auditorium. There are 7 seats in each row. There are 70 people seated, filming up full rows of

AleksandrR [38]

6 rows are empty.

112/7 = 16 rows

70/7 = 10 rows used.

4 0

2 years ago

-3 = b/6 - 10 * B/6 IS DIVISION NOT A FRACTION* Thank you

vodka [1.7K]

Answer:

bro division and fraction are technically same

Step-by-step explanation:

8 0

1 year ago

Read 2 more answers

Angle n and angle p are linear pairs, and angle n is 10 more than twice the measure of angle p. Determine the measure of angle p

frutty [35]

Answer:

p = 56.7°

n = 123.3°

Step-by-step explanation:

The sum of linear pair angles is 180° because, because a linear pair angles, are angles formed by two intersected lines and the angle of a straight line is 180°.

Then your first equation is:

n + p = 180°

The second equation can be formulated with the information given:

"angle n is 10 more than twice the measure of angle p."

n = 10 + 2p

Replacing in the first equation:

10 + 2p + p = 180°

3p = 170°

p = 56.7°

n = 123.3°

5 0

2 years ago

A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy

aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) $\bar{B}$ y $P(\bar{B})$ =0.5 (c) $\bar{A}$ ∪ $\bar{B}$ y P( $\bar{A}$ ∪ $\bar{B}$ ) = 0.9 (d) $\bar{A}$ ∩ $\bar{B}$ y P( $\bar{A}$ ∩ $\bar{B}$ )=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P( $A\cap \bar{B}$ ) = 0.3, P( $B\cap \bar{A}$ ) = 0.4 and P( $A\cap B$ ) = 0.1

(a) P(A) = P( $A\cap (B\cup\bar{B})$ ) = P( $A\cap B$ ) + P( $A\cap \bar{B}$ ) = 0.1 + 0.3 = 0.4

(b) P(B) = P( $B\cap (A\cup\bar{A})$ ) = P( $B\cap A$ ) + P( $B\cap \bar{A}$ ) = 0.1 + 0.4 = 0.5

P( $\bar{B}$ ) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e., $\bar{A}$ , and the customer does not buy from outlet 2 is the complement of B, i.e., $\bar{B}$ , so, the customer does not buy from outlet 1 or does not buy from outlet 2 is $\bar{A}$ ∪ $\bar{B}$ and P( $\bar{A}$ ∪ $\bar{B}$ ) = P( $(A\cap B)^{c}$ ) by De Morgan's laws

P( $(A\cap B)^{c}$ ) = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to $\bar{A}$ ∩ $\bar{B}$ and P( $\bar{A}$ ∩ $\bar{B}$ ) = P( $(AUB)^{c}$ ) by De Morgan's laws, and

P( $(AUB)^{c}$ ) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0

2 years ago