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goblinko [34]
3 years ago
15

Ricardo llega cada mañana a su trbajo con 5 minutos de retraso. Cúanto dinero le descuentan al cabo de 30 dIas si por cada hora

tiene una multa de s/2,80
Mathematics
1 answer:
Reika [66]3 years ago
4 0

Respuesta:

7

Explicación paso a paso:

Dado :

Último minuto por día = 5 minutos

Número de retrasos = 3 días

Número total de minutos tarde = (30 * 5) = 150 minutos

Cargo por multa por pago tardío por hora = 2,80

Total de horas tardías = 150 minutos / 60 = 2,5 horas

Cargo total por multa por mora = 2.80 * 2.5

Cargo total por multa por mora = 7

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If x = -4, then - (-x) = 4.<br> O True<br> O False<br> Quick Nav
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Answer:

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Can someone explain how to convert a quadratic function in standard form to vertex form using the "complete the square" method?
Arisa [49]

The required steps are explained below to convert the quadratic function into a perfect square.

<h3>What is the parabola?</h3>

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

Let the quadratic function be y = ax² + bx + c.

The first step is to take common the coefficient of x². We have

\rm y = a \left (x^2 + \dfrac{b}{a}x \right) + c

Add and subtract the half of the square the coefficient of x,

\rm y = a \left (x^2 + \dfrac{b}{a}x + \dfrac{b^2}{4a^2} \right) - a \times \dfrac{b^2}{4a^2} + c

Then we have

\rm y = a \left (x + \dfrac{b}{a} \right)^2 - \dfrac{b^2}{4a} + c

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3 0
2 years ago
A magician performing a magic act has asked for 2 volunteers from the audience to help with his routine. If there are 250 people
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The answer is 125. If you were to pair 250 people in 2, that would be 250 divided by 2. And 250 divided by 2 is 125.
5 0
3 years ago
Read 2 more answers
Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
3 years ago
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