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Salsk061 [2.6K]
3 years ago
9

A forest is cut down to make room for a housing development. Which population is most likely to survive? A. raccoons, which can

eat a variety of foods B. woodpeckers, that need to nest in a particular tree C. large predators that need to hunt over a wide area D. salamanders that hibernate in rotting logs
Chemistry
1 answer:
Basile [38]3 years ago
5 0
A. Raccoons. They will be able to survive in a housing area just as well, or even better then they had in the forrest.

I hope that helped! :D
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Zinc and magnesium metal each reacts with hydrochloric acid to make chloride salts of the respective metals, and hydrogen gas. a
kirill115 [55]
M=11.20 g
m(H₂)=0.6854 g
M(H₂)=2.016 g/mol
M(Mg)=24.305 g/mol
M(Zn)=65.39 g/mol
w-?

m(Mg)=wm
m(Zn)=(1-w)m

Zn + 2HCl = ZnCl₂ + H₂
m₁(H₂)=M(H₂)m(Zn)/M(Zn)=M(H₂)(1-w)m/M(Zn)

Mg + 2HCl = MgCl₂ + H₂
m₂(H₂)=M(H₂)m(Mg)/M(Mg)=M(H₂)wm/M(Mg)

m(H₂)=m₁(H₂)+m₂(H₂)
m(H₂)=M(H₂)(1-w)m/M(Zn)+M(H₂)wm/M(Mg)=M(H₂)m{(1-w)/M(Zn)+w/M(Mg)}

m(H₂)=M(H₂)m{(1-w)/M(Zn)+w/M(Mg)}

(1-w)/M(Zn)+w/M(Mg)=m(H₂)/{M(H₂)m}

1/M(Zn)-w/M(Zn)+w/M(Mg)=m(H₂)/{M(H₂)m}

w(1/M(Mg)-1/M(Zn))=m(H₂)/{M(H₂)m}-1/M(Zn)

w=[m(H₂)/{M(H₂)m}-1/M(Zn)]/(1/M(Mg)-1/M(Zn))

w=0.583 (58.3%)
5 0
3 years ago
2. What is the weight of the hydrochloric acid that fills a 144.5 mL container? The density of
hoa [83]
I don’t understand the question sorry
8 0
2 years ago
Anybody Understand this question please help me !
zlopas [31]

Answer:

m_{Sn}=630.57gSn

Explanation:

Hello!

In this case, according to the chemical reaction:

SnO_2+2H_2\rightarrow Sn+2H_2O

We can evidence the 2:1 mole ratio between hydrogen and tin, thus, we perform the following stoichiometric setup to obtain the mass of produced tin:

m_{Sn}=21.46gH_2*\frac{1molH_2}{2.02gH_2}*\frac{1molSn}{2molH_2} *\frac{118.71gSn}{1molSn} \\\\m_{Sn}=630.57gSn

Best regards!

7 0
3 years ago
The freezing point of water is 0.00°C at 1 atmosphere. How many grams of nickel(II) sulfate (154.8 g/mol), must be dissolved in
VladimirAG [237]

Answer:

adsf

Explanation:

dzfgx

5 0
3 years ago
Plz help!!!
baherus [9]

a) The change here is that metallic iron is converted into ions and copper is deposited. This is called a displacement reaction.

b) \text{Fe} is oxidised in this reaction.

c)$ \mathrm{Fe_{(s)}+ CuSO_{4(aq)} \rightarrow FeSO_{4(aq)} + Cu_{(s)}}$

7 0
3 years ago
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