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Serga [27]
4 years ago
11

In a sedimentary rock, small rounded particles indicate a A) long distance and long travel time. B) long distance and short trav

el time. C) short distance and long travel time. D) short distance and short travel time
Chemistry
1 answer:
mafiozo [28]4 years ago
6 0

Answer:

A) long distance and long travel time.

Explanation:

Sedimentary rocks are the rocks which are created by the accumulation or the deposition of minute particles as well as subsequent cementation of the  mineral or the organic particles on floor of the bodies of the water at the  surface of the Earth.

Sediment Maturity is the duration of the time that sediments have been in sedimentary cycle. <u>Texturally, mature sediments are that which are well rounded, (the process of rounding for the sediments increases with the transport distance as well as the time) as well as well sorted (the process of sorting for the sediments gets better as the larger clasts are astray and the smaller clasts are carried away , which also means the sediments travel longer distance).</u>

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The barium isotope 133ba has a half-life of 10.5 years. a sample begins with 1.1×1010 133ba atoms. how many are left after (a) 5
Sladkaya [172]
<span>a) 7.9x10^9 b) 1.5x10^9 c) 3.9x10^4 To determine what percentage of an isotope remains after a given length of time, you can use the formula p = 2^(-x) where p = percentage remaining x = number of half lives expired. The number of half lives expired is simply x = t/h where x = number of half lives expired t = time spent h = length of half life. So the overall formula becomes p = 2^(-t/h) And since we're starting with 1.1x10^10 atoms, we can simply multiply that by the percentage. So, the answers rounding to 2 significant figures are: a) 1.1x10^10 * 2^(-5/10.5) = 1.1x10^10 * 0.718873349 = 7.9x10^9 b) 1.1x10^10 * 2^(-30/10.5) = 1.1x10^10 * 0.138011189 = 1.5x10^9 c) 1.1x10^10 * 2^(-190/10.5) = 1.1x10^10 * 3.57101x10^-6 = 3.9x10^4</span>
4 0
3 years ago
Read 2 more answers
A 1M solution is made of each item in a pair. When would this combination create a buffer? Chose the pairs below that you could
monitta

Answer:

b. HCOOH/ NaHCOO.

Explanation:

A buffer system may be formed in one of two forms:

  • A weak acid with its conjugate base.
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Chose the pairs below that you could use to make a buffered solution.

a. HCI/NaOH. NO. HCl is a strong acid and NaOH is a strong base.

b. HCOOH/ NaHCOO. YES. HCOOH is a weak acid and HCOO⁻ (coming from NaHCOO) is its conjugate base.

c. HNO₂/H₂SO₃. NO. Both are acids and they are unrelated to each other.

d. NaNO₃/ HNO₃. NO. HNO₃ is a strong acid.

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2 years ago
What is work and state the law of conservation mass?<br>​
Butoxors [25]

Answer:

Work is a force causing the movement or displacement of an object

law of conservation mass:

1. Atoms cannot be created or destroyed in a chemical reaction.

2. Molecules cannot be created or destroyed in a chemical reaction.

3. Compounds cannot be created or destroyed in a chemical reaction.

4. Heat cannot be created or destroyed in a chemical reaction.

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