Answer: Please see attachment.
Solution:
We need to match the column using column proof. Please see the attachment for matching column.
In ΔDOC and ΔBOA
DO=BO (Given)
∠DOC=∠BOA (Vertically Opposite angle)
OC=OA (Given)
∴ ΔDOC ≅ ΔBOA by SAS congruence property
∠1=∠2 and AB=DC By CPCTE
Thus, AB||DC (∠1 and ∠2 are alternate angles equal then lines parallel)
ABCD is a parallelogram. ( If two sides equal and parallel then a parallelogram.
Below is matched table.
DO = OB, AO = OC ⇒ Given
∠ DOC =∠ AOB ⇒ Vertical angles are equal
∆COD ≅ ∆AOB ⇒ SAS CPCTE
∠1 = ∠2, AB = DC ⇒ CPCTE
AB||DC ⇒ If alternate interior angles =, then lines parallel
ABCD is a parallelogram ⇒ If two sides = and ||, then a parallelogram
Please see attachment for figure and matching.
This will be false a box plot is also known as quantile plots
1. Make shore u give the right money
2. Don't be rude if they don't have what u want
3. Don't steal and lie about it
Answer:
u-3>-6
Step-by-step explanation:
Just ask.
Hope this helps.
Answer:
26 y + 5
Step-by-step explanation:
Simplify the following:
7 3 y + 4 3 y - 3 y - 2 2 y + 5
7×3 = 21:
21 y + 4 3 y - 3 y - 2 2 y + 5
-2×2 = -4:
21 y + 4 3 y - 3 y + -4 y + 5
4×3 = 12:
21 y + 12 y - 3 y - 4 y + 5
Grouping like terms, 21 y + 12 y - 3 y - 4 y + 5 = (21 y - 4 y + 12 y - 3 y) + 5:
(21 y - 4 y + 12 y - 3 y) + 5
21 y - 4 y + 12 y - 3 y = 26 y:
Answer: 26 y + 5