Answer:
c.
Step-by-step explanation:
The equation which represents the circle is x²+(y-3)²=36. The correct option is A.
Given that the circle have diameter 12 units and a center that lies on the y-axis.
A circle is a closed curve drawn from a fixed point called the center, and all points on the curve are equidistant from the midpoint of the center.
The standard form for finding the equation of a circle is expressed in the form is
(x-a)²+(y-b)²=r² ......(1)
Where (a,b) is the center and r is the radius.
Given that the diameter is 12.
So, the radius is 12/2=6
It is also given that center lies on the y-axis therefore the center will be (0,3).
Now, we will substitute these values in equation (1), we get
(x-0)²+(y-3)²=6²
x²+(y-3)²=36
Hence, the equation which represents the circle with diameter 12 units and center lies on the y-axis is x²+(y-3)²=36.
Learn more about the equation of circle from here brainly.com/question/24810873
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Answer: 0.1
Step-by-step explanation:
The average value of a continuous function f(x) over an interval [a, b] is
![\displaystyle f_{\mathrm{ave}[a,b]} = \frac1{b-a}\int_a^b f(x)\,dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f_%7B%5Cmathrm%7Bave%7D%5Ba%2Cb%5D%7D%20%3D%20%5Cfrac1%7Bb-a%7D%5Cint_a%5Eb%20f%28x%29%5C%2Cdx)
We're given that
![\displaystyle f_{\rm ave[-1,2]} = \frac13 \int_{-1}^2 f(x) \, dx = -4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f_%7B%5Crm%20ave%5B-1%2C2%5D%7D%20%3D%20%5Cfrac13%20%5Cint_%7B-1%7D%5E2%20f%28x%29%20%5C%2C%20dx%20%3D%20-4)
![\displaystyle f_{\rm ave[2,7]} = \frac15 \int_2^7 f(x) \, dx = 8](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f_%7B%5Crm%20ave%5B2%2C7%5D%7D%20%3D%20%5Cfrac15%20%5Cint_2%5E7%20f%28x%29%20%5C%2C%20dx%20%3D%208)
and we want to determine
![\displaystyle f_{\rm ave[-1,7]} = \frac18 \int_{-1}^7 f(x) \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f_%7B%5Crm%20ave%5B-1%2C7%5D%7D%20%3D%20%5Cfrac18%20%5Cint_%7B-1%7D%5E7%20f%28x%29%20%5C%2C%20dx)
By the additive property of definite integration, we have
so it follows that
![\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(\int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx\right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f_%7B%5Crm%20ave%5B-1%2C7%5D%7D%20%3D%20%5Cfrac18%20%5Cleft%28%5Cint_%7B-1%7D%5E2%20f%28x%29%5C%2Cdx%20%2B%20%5Cint_2%5E7%20f%28x%29%5C%2Cdx%5Cright%29)
![\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(3\times(-4) + 5\times8\right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f_%7B%5Crm%20ave%5B-1%2C7%5D%7D%20%3D%20%5Cfrac18%20%5Cleft%283%5Ctimes%28-4%29%20%2B%205%5Ctimes8%5Cright%29)
![\displaystyle f_{\rm ave[-1,7]} = \boxed{\frac72}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f_%7B%5Crm%20ave%5B-1%2C7%5D%7D%20%3D%20%5Cboxed%7B%5Cfrac72%7D)
It would be 0.2
Because
1 divided by 5 = 0.2
To check
0.2*5=1
Hope this helps
Have a great day/night
