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3 years ago

Answer the question in the picture pls WORTH 50 POINTS PLUS BRAINLIEST FOR FIRST CORRECT ANSWER

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

6 0

Answer:

Step-by-step explanation:

| 4-y| ≥8

Separate into two inequalities, one positive and one negative (remembering to flip the inequality)

4-y ≥8 or 4-y≤ -8

Solve

Subtract 4 from all sides

4-y -4 ≥8-4 or 4-y-4≤ -8-4

-y ≥4 or -y≤ -12

Divide each side by -1, remembering to flip the inequality

y ≤-4 or y ≥12

The smallest positive number is 12

Alexus [3.1K]3 years ago

5 0

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−y+4≥8

Step 2: Subtract 4 from both sides.

−y+4−4≥8−4

−y≥4

Step 3: Divide both sides by -1.

−y

−1

≥

−1

y≤−4

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When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o

Roman55 [17]

Answer:

Option C.

Step-by-step explanation:

Given information:

Sample size = 150

Number of Opinions = 3 (Yes, No, No Opinion)

Yes = 40

No = 60

No opinion = 50

We need to find the expected frequency for each group.

Expected frequency for each group is the quotient of sample size and number of opinions.

$\text{Expected frequency for each group}=\dfrac{\text{Sample size}}{\text{Number of Opinions}}$

$\text{Expected frequency for each group}=\dfrac{150}{3}$

$\text{Expected frequency for each group}=50$

Therefore, the correct option is C.

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3 years ago

A certain species of tree grows an average of 0.5 cm per week. Write an equation for the sequence that represents the weekly hei

Anestetic [448]

For this we will use equation:

H = starting height + rate_of_growth*periods
We can mark H with index w to represent how many weeks have passed.
Because all of this we can write:

Hw = 200 + 0.5*w

To calculate height after some number of weeks all you need to do is to exchange w with number of weeks.

4 0

4 years ago

A process that fills packages is stopped whenever a package is detected whose weight falls outside the specification. Assume tha

swat32

Answer:

The mean number of packages that will be filled before the process is stopped is 50.

Step-by-step explanation:

For each package, there are only two possible outcomes. Either it fails outside the specifications, or it does not. Packages are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Number of trials expected for n sucesses

Also called inverse binomial distribution, is given by:

$E = \frac{n}{p}$

In which p is the probability of a success in a trial.

Assume that each package has probability 0.02 of falling outside the specification and that the weights of the packages are independent.

This means that $p = 0.02$

Find the mean number of packages that will be filled before the process is stopped.

This is when $n = 1$ , as the process is stopped when a package is outside the specifications. So

$E = \frac{n}{p} = \frac{1}{0.02} = 50$

The mean number of packages that will be filled before the process is stopped is 50.

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3 years ago

Three angles are in the ratio 2 : 3 : 5 The smallest angle is 50 degrees Work out the sizes of the other two angles

Oxana [17]

Since the smallest angle is 50 degrees, then divide 50 by 2 (because of the ratio) and you get 25. Now you can multiply 25 by 3 and 25 by 5 to get the remaining angles which would be 75 degrees and 125 degrees.

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3 years ago

The distances (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by the equations b

Harlamova29_29 [7]

2hrs, 142miles
42x+58=55x+32
13x=26
x=2hrs <---- answer
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55*2+32=142mi <----answer

7 0

3 years ago

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