Answer:
Width = x-1
Step-by-step explanation:
Given
Area of rectangle=A= x^4+4x^3+3x^2-4x-4
Length of Rectangle=L= x^3+5x^2+8x+4
We have to find width
Width of rectangle=W= ?
We know that the formula for the area of triangle is:
Area of Rectangle=Length*Width
A=L*W
Since we need the value of width, length will be moved to the left of equals to.
A/L=W
W= (x^4+4x^3+3x^2-4x-4)/(x^3+5x^2+8x+4)
After long division, we will get
Width=W=x-1
Answer:
1. 50%
2. 25%
or
1. 26/52 (simplify= 13/26)
2. 13/52
Step-by-step explanation:
For this case we can define the following variable:
x: unknown number
We write the equation that models the problem:
From here, we clear the value of x.
We have then:
Answer:
Completing the sentence we have:
0.04 is 1/10 of 0.40
A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
