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3 years ago

14

Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is worth either

5 points or 2 points. Write a system of equations that can be used to find how many problems of each point value are on the test. Let x be the number of questions worth 5 points and let y be the number of questions worth 2 points. x + y = 29, 5x + 2y = 100 x + y = 100, 5x + 2y = 29 5x + y = 29, 2y + x = 100 2x + y = 100, 5y + x = 29v

2 answers:

Sloan [31]3 years ago

7 0

Answer: The answer is A: x + y = 29, 5x + 2y = 100.

hope this helps you (:

Alborosie3 years ago

3 0

Answer:

x + y = 29

5x + 2y = 100

Step-by-step explanation:

Total problems = 29

x + y = 29

Total marks for 5 point problems = 5*x = 5x

Total marks for 2 point problems = 2*y = 2y

Total marks = 100

5x + 2y = 100

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Answer:

1) The graph labeled and the ordered pairs plotted are shown in the second picture.

2) To calculate the amount of meat (in pounds) needed for a party of 75 people:

Substitute the value of the Constant of proportionality and $x=75$ into the equation $y=kx$ and then evaluate (The result is 30 pounds).

Step-by-step explanation:

<h3> The missing graph is attached.</h3>

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$y=kx$

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1) You can observe in the graph shown in the first picture this point:

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So you can subsitute the coordinates of this point into $y=kx$ and solve for "k":

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<u>For 20 people</u>

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$y=(\frac{2}{5})(40)=16$

The ordered pair is:

$(40,16)$

<u>For 50 people</u>

Substituting $k=\frac{2}{5}$ and $x=50$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(50)=20$

The ordered pair is:

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2) Substituting $k=\frac{2}{5}$ and $x=75$ into the equation $y=kx$ and evaluating, you can calculate the amount of meat (in pounds) needed for a party of 75 people. This is:

$y=(\frac{2}{5})(75)=30$

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ololo11 [35]

Answer:

#2- A

#3- D

#4-1

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