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statuscvo [17]
3 years ago
8

25 2 In long division

Mathematics
1 answer:
Andre45 [30]3 years ago
3 0

Answer:

..........

Step-by-step explanation:

i don't understand 25 2 ??

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The answer choices are -3, 3/2, 3, and -12/5.<br> thanks in advance!! :)
BabaBlast [244]

Answer:

<em>(C). {3} </em>

Step-by-step explanation:

\frac{x}{2(x+1)} = \frac{-2x}{4(x+1)} + \frac{2x-3}{x+1} ( x ≠ - 1 )

\frac{x}{2(x+1)} - \frac{2x-3}{x+1} + \frac{x}{2(x+1)} = 0

\frac{2x-3}{x+1} - \frac{x}{(x+1)} = 0

\frac{x-3}{x+1} = 0 ⇒ <em>x = 3</em>

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3 years ago
Find the volume of the cone. Round your answer to the nearest tenth if necessary. Use 3.14 for π.
Doss [256]

Answer:

I think the answer is 287.98

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Which graph represents the inequality?
Alecsey [184]

it will be a hope that helps what

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What’s the diameter of a circle 5in
Molodets [167]

Answer:

About 1.591 in

Step-by-step explanation:

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3 years ago
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Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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