Question

A box of 42 chocolates contains milk and dark chocolates in the ratio of 3:4. How many chocolates of each type there are?

Answer 1

Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.

Step-by-step explanation:

Let the number of milk chocolates be $m$.

Let the number of dark chocolates be $d$.

Given that the box contains the milk and dark chocolates in the ratio $3:4$.

So,$\frac{m}{d}=\frac{3}{4}$               ...(i)

Given that the total number of chocolates are $42$.

So,$m+d=42$.                                   ...(ii)

Using (i) and (ii),

$m+\frac{4}{3}m=42$

$\frac{7}{3}m=42$

$m=18$

$d=\frac{4}{3}m=\frac{4}{3}\times 18=24$

So,the number of milk chocolates are $18$ and the number of dark chocolates are $24$.