Answer:
7/4 which could also be written as 1 and 3/4
Slope itnercept is y=mx+b
ok, let's start with point slope form
y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m
so given point (-3,4) and slope -3/4
y-4=-3/4(x-(-3))
y-4=-3/4(x+3)
distribute to solve for y
y-4=(-3/4)x-9/4
add 4 to both sides
y=(-3/4)x-9/4+4
y=(-3/4)x-9/4+16/4
y=(-3/4)x+7/4
Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
I believe it is context clues. The reader typically looks for context clues to understand the reading.
