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3 years ago

The function c(r)=2r+12.5 represents the cost c, in dollars, of riding r rides

Mathematics

1 answer:

Damm [24]3 years ago

3 0

So basically i think it is c or maybe b do inie meni myni mo

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Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position

Ipatiy [6.2K]

Answer:

Part A) Not collide

Part B) k = 4

Part C) Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

Position of particle A:-

$x(t)=5t-5$

$y(t)=2t-k$

Position of particles B:-

$x(t)=4t$

$y(t)=t^2-2t+1$

Part A) For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, $(4t,t^2-2t-1)$

If both collides then x and y coordinate must be same

Therefore,

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t+6=t^2-2t-1$

$t^2-4t-7=0$

$t=-1.3,5.3$

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t-k=t^2-2t-1$

Put t = 5

$10-k=25-10-1$

$k=4$

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, $\dfrac{dA}{dt}$

$\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4$

Speed of particle B, $\dfrac{dB}{dt}$

$\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}$

At t = 5

$\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2$

Hence, Particle B moves faster than particle A

8 0

3 years ago

The answer is Infinitely many solutions

MAVERICK [17]

Answer:

what is the question?????????????

4 0

3 years ago

Which of the algebraic expressions are not linear expressions? Select all that apply. a. 3x - 2 b. -9y c. -7x^2^ + 4x d. -1/2x^2

Sedaia [141]

Answer:

c, d and e

Step-by-step explanation:

A linear expression is an expression in which sum of exponents of variables is at most 1 in each of its terms.

Option a: $3x - 2$

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option b: $-9y$

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option c: $-7x^2 + 4x$

Here, the highest exponent of the variable is 2.

So, it is NOT a linear expression.

Option d: $-\frac{1}{2} x^2$

Here, the exponent of the variable is 2.

So, it is NOT a linear expression.

Option e: $8xy$

Here, sum of exponents of variables is 2.

So, it is NOT a linear expression.

Hence, c, d and e are NOT algebraic expressions.

6 0

3 years ago

Okay so the choices of answers are the same on all three and I do need answers for all three :( pls help! Thanks

vovikov84 [41]

Answer:

1. >

2. <

3. =

Step-by-step explanation:

7 0

4 years ago

What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction?

dlinn [17]

Step-by-step explanation:

${x}^{2} = \frac{9}{16} \\ first \: step : \: take \: square \: root \: of \: both \\ sides. \\ \sqrt{ {x}^{2} } = \pm \sqrt{\frac{9}{16} } \\ x = \pm \frac{3}{4} \\$

8 0

3 years ago

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