The function c(r)=2r+12.5 represents the cost c, in dollars, of riding r rides

If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?

Lyrx [107]

May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x

1) If h(x) = 5x and k(x) = 1/x

Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)

2) If h(x) = 5 + x and k (x) = 1/x

Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]

4 0

2 years ago

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The measure of an interior angle of a regular octagon is how many degrees greater than the measure of an interior angle of a reg

harina [27]

Answer:

Step-by-step explanation:

Sum of interior angle of any polygon = 180* (n- 2 )

Here, n= number of sides

Sum of interior angles of regular octagon = 180 * ( 8-2) = 180 * 6 = 1080°

In regular octagon, all the angles are congruent,

So, measure of an interior angle of regular octagon = 1080/8 = 135°

Sum of interior angles of regular hexagon = 180 * ( 6-2) = 180*4 = 720°

In regular hexagon, all the angles are congruent,

So, measure of an interior angle of regular hexagon = 720/6 = 120°

The measure of an interior angle of a regular octagon is greater than the measure of an interior angle of a regular hexagon by 15°

3 0

3 years ago

Which of the following demonstrates the Commutative Property of addition?

Crazy boy [7]

Answer:

To my calculations, I think its the first one, 4+2=2+4

I hope this helps! ^^

Apologizes if you get it wrong-

Step-by-step explanation:

5 0

2 years ago

A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength

irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

Let $\bar X$ = sample mean comprehensive strength

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean comprehensive strength = 5500 psi

$\sigma$ = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P( $\bar X$ > 4985 psi)

P( $\bar X$ > 4985 psi) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{4985-5500}{\frac{100}{\sqrt{9} } }$ ) = P(Z > -15.45) = P(Z < 15.45)

= 0.99999

Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.

4 0

3 years ago

Please help. I will give brainliest immediately.

DerKrebs [107]

Answer:

I'm pretty sure it is d, 5/22

7 0

2 years ago