Need help please<br> thanks

If a hen and a half lays a egg and a half for a cent and a hald how much does a dozen cost

slavikrds [6]

12 cents because 3/2 hens make 3/2 of an egg for 3/2 cents. Multiplying each part of the equation by 2/3 means you get 1 hen = 1 egg = 1 cent. Since there are twelve eggs in a dozen, you pay 12 cents.

8 0

2 years ago

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Evaluate the expression x=7 18-1.8x=

ElenaW [278]

18-1.8x= ?

x = 7

So, substitute the number in for the x

18-1.8*7

18-12.6=5.4

5.4 is your answer

-IronWolfX✔

5 0

2 years ago

Math is not my thing! Can you help?

aksik [14]

Answer:

12

Step-by-step explanation:

Equation: 5x + 9 - 4x

Plug in x = 3

New equation: 5(3) + 9 - 4(3)

Simplify: 15 + 9 - 12

Simplify: 12

<u>Answer: 12</u>

8 0

2 years ago

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Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9

tatiyna

Answer:

The solution to the system of equations is

$\begin{gathered} x=\frac{179}{13} \\ \\ y=-\frac{279}{39} \\ \\ z=-\frac{48}{13} \end{gathered}$

Explanation:

Giving the system of equations:

$\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}$

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

$5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)$

Subtracting (3) from 3 times (1), we have

$3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)$

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

$\begin{gathered} 13z=-48 \\ \\ z=-\frac{48}{13} \end{gathered}$

Using the value of z obtained in (5), we have

$\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\ \\ 3y+\frac{240}{13}=-3 \\ \\ 3y=-3-\frac{240}{13} \\ \\ 3y=-\frac{279}{13} \\ \\ y=-\frac{279}{39} \end{gathered}$

Using the values obtained for y and z in (1), we have

$\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\ \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\ \\ x-\frac{231}{13}=-4 \\ \\ x=-4+\frac{231}{13} \\ \\ x=\frac{179}{13} \end{gathered}$

8 0

10 months ago

The table below shows the amount of money needed to buy certain amounts of fabric. Fabric Cost Yards of Fabric Total Cost 3 $5.2

tino4ka555 [31]

$21, due to $5.75 being added for every three yards.

8 0

2 years ago

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Need help please thanks