Answer:
Option A
Step-by-step explanation:
Here is how to approach the problem:
We see that all our restrictions for all four answer choices are relatively the same with a couple of changes here and there.
One way to eliminate choices would be to look at which restrictions don't match the graph.
At x<-5, there is a linear function that does have a -2 slope and will intersect the x axis at -7. The line ends with an open circle, so any answer choice with a linear restriction of x less than or equal to -5 is wrong. This cancels out choices C and D.
Now we have two choices left.
For the quadratic in the middle, the vertex is at (-2,6) and the vertex is a maximum, meaning our graph needs to have a negative sign in front of the highest degree term. In our case, none of our quadratics left are in standard form, and instead are in vertex form.
Vertext form is f(x) = a(x-h)^2 + k.
h being the x-coordinate of the vertex and k being the y-coordinate.
We know that the opposite of h will be the actual x-coordinate of the vertex, so if our vertex is -2, we will see x+2 inside the parenthesis. This leaves option A as the only correct choice.
Answer:
candles = $400
matches = $20
Step-by-step explanation:
Let cost of candles = $c
Let cost of matches = $m
c = 20 m (20 times m)
c + m = 420
20m + m = 420
21 m = 420
m = 20
c = 20 (20) = 400
I think it is the tens because the first is ten thousand, second is thousand, third is hundreds and last is units ones
Answer:
V=3926.99 liters
Step-by-step explanation:
cylindrical Is half full of oil The cylinder Has a base radius of 100 cm The height of the cylinder 250cm 1 litres = 1000cm3 How many litres of oil are in the tank?
Volume of a cylinder can be calculated using below formula
V=π r^2 h
Where r= radius
h= height
radius = 100 cm
h=250cm
But the cylinder is half filled, then the formula becomes
V=(π r^2 h) × 1/2
Then substitute the values we have
V=( π × 100^2 ×250) × 1/2
V=3926990 cm^3
But 1 litres = 1000cm3
Then V=(3926990 cm^3)/ 1000
V=3926.99 liters
B. I am so sorry if it is not right
