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LiRa [457]
3 years ago
13

In reducing one's speed from 70 mph to 50 mph, how much of a percentage decrease in stopping distance is realized (to the neares

t percent)?

Mathematics
1 answer:
Ghella [55]3 years ago
4 0

we are given relation between speed and distance

distance ( when speed =70mph) is

=328feet

so, d_1=328

distance ( when speed =50mph) is

=183feet

so, d_2=183

now, we can find percentage in decrease

=\frac{d_1-d_2}{d_1}\times 100

now, we can plug values

=\frac{328-183}{328}\times 100

=44%...........Answer

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Required

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