Answer: x = 0.6 ÷ 8.9 = 5.34
Step-by-step explanation:
1 can of wet food
_
3 cans of wet food
Or
1:3
Answer:
0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 7.2 minutes and a standard deviation of 2.1 minutes.
This means that 
For a randomly received emergency call, find the probability that the response time is between 3 and 9 minutes.
This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 3.
X = 9



has a pvalue of 0.8051
X = 3



has a pvalue of 0.0228
0.8051 - 0.0228 = 0.7823
0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.
Answer:
900 front row seats
Step-by-step explanation:
Tickets for front row seat = 220 dollars (y)
Cost of remaining seats ticket = 50 dollars (z)
Number of front row seats = x
Number of remaining seats = 2050 (w)
Total amount earned when stadium is full = 300,500 dollars (T)
so if we formulate this using our variables y,z,x,w and T problem it becomes:
y*x + z*w = T, which says the
Tickets for front row seat times Number of front row seats plus Cost of remaining seats ticket times Number of remaining seats gives us Total amount earned by the stadium.
220*x + 2050*50 = 300500
220*x = 300500-102500
220*x = 198000
divide both side by 220
x = 900
Answer:
pie * r^2 bro where r= 10mi