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2 years ago

PLS HELP.....

Mathematics

1 answer:

Gemiola [76]2 years ago

3 0

The second one because Idk I’m just guessing lol it doesn’t look like it should be there though

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Directions: Find the volume of each figure. Round to the nearest tenth if necessary.

balu736 [363]

Answer:

Step-by-step explanation:

square-based pyramid:

volume V = (⅓)b²h

= (⅓)7²·16

≅ 261.3 ft³

:::::

Can't help with question 3. I haven't learned triangle-based pyramids.

:::::

cone:

volume V = ⅓πr²h

= ⅓π17²·20

= 6052.8 yd³

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can't help with question 7. Never did this kind of pyramid.

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2 years ago

Sweets cost 6p how much would 43 sweets cost?

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The answer is 258 pennies

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3 years ago

5x - 4y = 17<br> 6x + 4y = -6

Otrada [13]

Answer:

x = 14.2 y=15.

Step-by-step explanation:

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2 years ago

Find the area of the shaded region. Round the nearest hundredth if necessary. YZ=14.2m

andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$A_1 = 67.58 \ in^2$

$A_2 =415.4 \ ft^2$

$A_3 = 8.48 \ cm^2$

$A_4 = 480.38 \ m^2$

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

$A = \frac{\theta}{360} * \pi r^2$

Now at $r_1 = 11 in$ and $\theta_1 = 64^o$

$A_1 = \frac{64}{360} * 3.142 * 11^2$

$A_1 = 67.58 \ in^2$

Now at $r_2 = 20 ft$ in and $\theta_2 = 119 ^o$

$A_2 = \frac{119}{360} * 3.142 * 20^2$

$A_2 =415.4 \ ft^2$

Now at $r_3 = 6.5 cm$ and $\theta_3 = 23 ^o$

$A_3 = \frac{23}{360} * 3.142 * 6.5 ^2$

$A_3 = 8.48 \ cm^2$

Now at $r_4 = 14.2 m$ and $\theta_4 = 360 -87 = 273 ^o$

$A_4 = \frac{273}{360} * 3.142 * 14.2^2$

$A_4 = 480.38 \ m^2$

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3 years ago

Dale drove 441 miles in 7 hours. At the same rate, how long would it take him to drive 315 miles?

AURORKA [14]

Answer:

5 Hours

Step-by-step explanation:

He’s going 63 MPH

441/7 = 63 MPH

315/63 = 5 Hours

5 0

2 years ago

Read 2 more answers