Answer: 8 inches
Explanation:
a^2 + b^2 = c^2
6^2 + b^2 = 10^2
36 + b^2 = 100
b^2 = 64
(Have to find the square root of 64)
= 8 inches
Step1: Find the area of the triangular lawn
Given, base of the triangle is y metres and the height is z metres
Area of the triangle =
2
1
× base × height
Therefore, area of the triangular lawn =
2
1
yz metre
2
.
Step 2:Find the cost of planting the grass
Rate of planting the grass is Rs. x per square metre.
Therefore, the cost of planting the grass on a triangular lawn =cost per square meter × area of the triangular lawn
=x×
2
1
yz=
2
1
xyz
Hence, the cost of planting the grass on a triangular lawn whose base is y metres and height is z metres is Rs.
2
1
x y z.
Step-by-step explanation:
<span>3.19459 seconds
Since we've been given the equation for how high the ball is at t seconds, all we need to do is solve for a height of 0. So
h = 67 - 5t - 5t^2
0 = 67 - 5t - 5t^2
And you should immediately notice that we have a quadratic equation with A = -5, B = -5, and C=67. Use the quadratic formula to determine the roots of -4.19459 and 3.19459. Since we can't have negative seconds, that means that the ball will hit the ground 3.19459 seconds after it was thrown.</span>
Answer:
19/100 or 5/26
Step-by-step explanation:
i think
Hello,
x<y<z (1)
xy=6b (2)
yz=8b (3)
xz=175 (4)
(2)/(3)==>x/z=6/8==>x=3z/4 (5)
(4) and (5)==>3z/4*z=175==>z²=700/3==>z=√(700/3) (6)
(5) and (6)==>x=3/4*√(700/3) (7)
(1) and (7) ==>3/4*√(700/3)<y<√(700/3) (8)
(8)*z==>3/4*√(700/3)*√(700/3)<yz<√(700/3)*√(700/3)
==>175<yz<700/3
