Answer:
Step-by-step explanation:
Hello!
Given the variables
X₁: Weight of a safety helmet for racers
X₂: Price of a safety helmet for racers
Note, there is n= 17 observed values for each variable so for all calculations I'll use this number and disregard the 18 mentioned in the text.
a) Scatterplot in attachment.
b) If you look at the diagram it seems that there is a negative linear regression between the price and the weight of the helmets, meaning, the higher the helmet weights, the less it costs.
c) The estimated regression equation is ^Yi= a + bXi
n= 17; ∑Y= 6466; ∑Y²= 3063392; ∑X= 1008; ∑X²= 60294; ∑XY= 367536
Y[bar]= 380.35; X[bar]= 59.29

![a= Y[bar]- bX[bar]= 380.35-(-30.18)*59.29= 2169.77](https://tex.z-dn.net/?f=a%3D%20Y%5Bbar%5D-%20bX%5Bbar%5D%3D%20380.35-%28-30.18%29%2A59.29%3D%202169.77)
The estimated regression equation for the price of the helmets as a function of their weight is:
^Yi= 2169.77 -30.18Xi
I hope it helps!
Answer:
184 in²
Step-by-step explanation:
Given :
Width, w = 6 inches
Length, l = 10 inches
Height, h = 2 inches
To obtain how much wrapping paper is needed ; we take the surface area of the box
Surface area = 2(lw + lh + wh)
Surface area = 2((6*10) + (6*2) + (10*2))
Surface area = 2(60 + 12 + 20)
Surface area = 2(92)
Surface area = 184 in²
The amount of wrapping paper needed = 184 in²
1. 2/3. Flip 2/3 into 3/2 and then multiply and simplify.
2. 30/91. Flip 7/6 to 6/7 and then multiply. You cannot simplify the fraction.
3. 26/27. Flip 9/10 to 10/9 and then multiply. You cannot simplify the fraction.
4. 44.2. Multiply it as if there was no decimal. Then count the number of digits after the decimal in each factor. Then put the same number of digits behind the decimal in the product.
5. 98.75. Multiply it as if there was no decimal. Then count the number of digits after the decimal in each factor. Then put the same number of digits behind the decimal in the product.
6. 3.36. Multiply it as if there was no decimal. Then count the number of digits after the decimal in each factor. Then put the same number of digits behind the decimal in the product.
7. 2. Multiply the divisor by as many 10’s as necessary until you get a whole number. Remember to multiply the dividend by the same number of 10’s. Then divide it normally.
8. 10.93 (rounded). Multiply the divisor by as many 10’s as necessary until you get a whole number. Remember to multiply the dividend by the same number of 10’s. Then divide it normally. I rounded it to the hundredth.
Hope this helps!