B is the answer because 12 divided by 6 is 2 and 18 divided by 6 is 3
Hey there! I'm happy to help!
First, let's find the radius. The radius is half of the diameter.
8.4/2=4.2
Here's how to find the area of a circle.
Square the radius.
4.2²=17.64
And multiply by pi (3.14 in our case)
17.64(3.14)=55.3896
We round to the nearest tenth, giving us an area of 55.4 ft²
Have a wonderful day! :D
Answer:
the answer is 1.16 shirts
Step-by-step explanation:
the mean absolute deviation is found by finding the average of the difference between each data point and the mean of the data.
1st...find the mean of the data by adding all the numbers according to the data plotted and dividing the by the numbers listed; which in this case is 10
1 +2+ 2+ 3+ 3+ 3+ 4+ 4+ 5+ 6 = 3.3
mean is 3.3
then find the difference between the mean and each data point
Data Point = 1 2 2 3 3 3 4 4 5 6
Difference from mean = 2.3 1.3 1.3 0.3 0.3 0.3 0.7 0.7 1.7 2.7
Find the average of these differences by adding the (differences from Mean) by 10
<u>2.3 + 1.3 + 1.3 + 0.3 + 0.3 + 0.3 + 0.7 + 0.7 + 1.7 + 2.7</u>
10
the mean absolute deviations is 1.16 shirts
Answer:
see explanation
Step-by-step explanation:
Parallel lines have equal slopes.
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 5x + 1 ← is in slope- intercept form
with slope m = 5
Rearrange 2y - 10x + 3 = 0 into this form
Add 10x to both sides
2y = 10x ( subtract 3 from both sides )
2y = 10x - 3 ( divide all terms by 2 )
y = 5x -
← in slope- intercept form
with slope m = 5
Since both lines have a slope of 5 then they are parallel.
Answer:
- solutions: (2, 10), (4, 5)
- non-solutions: all other points
Step-by-step explanation:
It can be useful to graph the inequalities related to Tyler's limits of money and weight.
1x +3y ≤ 36 . . . . . . the limit on the cost of the items Tyler can afford
1x +1.5y ≤ 20 . . . . . the limit on the weight of the items Tyler can carry
Then plotting the given points shows that only (2, 10) and (4, 5) are in the doubly-shaded area that is the solution space. The other points are not a solution.