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Aleksandr [31]
3 years ago
13

The value 5 is a an upper bound for the zeros of the function shown below f(x)=x^4+x^3-11x^2-9x+18

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

Answer to this question is TRUE.

Step-by-step explanation:

The graph of the function:

f(x)=x^4+x^3-11x^2-9x+18  is attached to the answer.

Clearly by looking at the graph we could see that the zeros of the function f(x) are <em>-3, -2, 1 and 3.</em>

All the zeros are distinct.

<em>" Also upper bound of a number 'p' means the set of all those numbers which are greater than 'p' ".</em>

Here 5 will be an upper bound for the zeros of the function f(x) since all the 4 zeros of f(x) are less than 5.

Hence, the given statement that the value 5 is an upper bound for the zeros of the function f(x) is TRUE.




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