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Aleksandr [31]
3 years ago
13

The value 5 is a an upper bound for the zeros of the function shown below f(x)=x^4+x^3-11x^2-9x+18

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

Answer to this question is TRUE.

Step-by-step explanation:

The graph of the function:

f(x)=x^4+x^3-11x^2-9x+18  is attached to the answer.

Clearly by looking at the graph we could see that the zeros of the function f(x) are <em>-3, -2, 1 and 3.</em>

All the zeros are distinct.

<em>" Also upper bound of a number 'p' means the set of all those numbers which are greater than 'p' ".</em>

Here 5 will be an upper bound for the zeros of the function f(x) since all the 4 zeros of f(x) are less than 5.

Hence, the given statement that the value 5 is an upper bound for the zeros of the function f(x) is TRUE.




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Suppose that F(x)=x^3 and G(x)=-5x^3. Which statement best compares the graph of G(x) with the graph of F(x)?
Vlad1618 [11]

Answer: The graph of G(x) is the graph of F(x) stretched vertically, flipped over the x-axis, and shifted 2 units up


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Require full steps working for this question
Ray Of Light [21]

I let the computer do the graphing.  

f(x) = x(x + 3)²(1 - x) / 3

We see obvious zeros at x=0, x=-3 and x=1.

f(x) = x(x + 3)²(1 - x) / 3

f(x) = x(x^2 + 6x + 9)(1 - x)/3

f(x) = x(x^2 + 6x + 9 - x^3 - 6x^2 - 9x)/3

f(x) = x(- x^3 - 5x^2 -3x +9)/3

f(x) = (-x^4 - 5x^3 -3x^2 +9x)/3

f'(x) = (-4x^3 - 15x^2 -6x + 9)/3

We know there's f'(-3)=0 so x+3 must be a factor here,

f'(x) = (x + 3) (-4x^2 - 3x + 3)

We get stationary points when x = -3 or

x = (-1/8)( 3 ± √(9 - 4(-4)(3))) =  (-3 ± √57)/8  about -1.3 and 0.6 which are a local minimum and maximum respectively.

f''(x) = (-12x^2 - 30x -6)/3 = -4x^2 - 10x - 2

f''(-3) = -4(9)+ 30 - 2 = -8

Concave Down, Negative.   (-3,0) is a local maximum.

f''((-3 - √57)/8) = -4(-1.3)^2 - 10(-1.3) - 2 = 4.24

Concave up, positive, a CUP

(-3 - √57)/8, f((-3 - √57)/8) ) is a minimum.

f''((-3 + √57)/8) = -4(.6)^2 - 10(.6) - 2 = -9.44

CDN, ( ((-3 + √57)/8), f((-3 + √57)/8) ) is a maximum.

I didn't evaluate f((-3 ±√57)/8) which are around -3 and 1 but I leave that calculation to you.

6 0
3 years ago
Graph the linear equation and answer each of the following questions. y=-2x-3
ollegr [7]

Answer:

Part 1) The y-intercept is the point (0,-3)

Part 2) The slope in fraction form is m=-\frac{2}{1}

Part 3) The graph in the attached figure

Step-by-step explanation:

we have

y=-2x-3

Part 1) What is the y-intercept?

Remember that

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

substitute in the linear equation and solve for y

y=-2(0)-3\\y=-3

The y-intercept is the point (0,-3)

Part 2) What is the slope (in fraction form)?

we have

y=-2x-3

This is the equation of the line in slope intercept form

y=mx+b

where

m is the slope or unit rate

b is the y-intercept

so

m=-2

In fraction form is

m=-\frac{2}{1}

The slope is negative, that means, is a decreasing function (as the x-values increases the y-values decreases)

Part 3) Graph the line

To graph the line we need two points

From the y-intercept (0,-3) use the slope to find your next point

The slope is -2, so you will rise -2 (2 units down) and run 1 (1 unit to the right).

The next point is (0+1,-3-2) -----> (1,-5)

so

Plot the points (0,-3) and (1,-5), connect them and graph the line

The graph in the attached figure

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Answer:

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Step-by-step explanation:

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Mashutka [201]

Answer:

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Step-by-step explanation:

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Divide both sides by - 5, reversing the symbol as a result of dividing by a negative quantity.

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