Answer D The binomial must start at 0, but can increase to an infinite upper limit. Hope that helps.
Correct Ans:Option A. 0.0100
Solution:We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.
First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.
Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
3, 12, 15, 25, 30, 40The range is the difference between the greatest and smallest values:
range = 40 - 3 = 37
Thee average is the sum of elements divided by the number of elements:
average = (<span>3 + 12 + 15 + 25 + 30 + 40</span>)/6
average = 125/6 = 20.83
Answer: the second one
Step-by-step explanation:
Answer:
a, ax3 =b, bx3= c , cx3=d, dx3=e
Step-by-step explanation:
2, 2×3=6, 6x3=18,18 x3 =54, 54x3= 162
Multiplication of three with previous number will give you next number in series.