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Vlada [557]
3 years ago
5

Please help me I will give Brainiest to who can answer first. :)

Mathematics
1 answer:
777dan777 [17]3 years ago
4 0

If 40% of the cameras are digital, that means 60% of them are not digital.

If 60% of all cameras is 24, then 20% is 8, making 40% 16 cameras.

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Don and Dan went fishing. Don caught 6 times more mass of fish than his brother. Together they caught 4.2 kg of fish. What mass
Nitella [24]

Answer:

Don caught 3.6 kg and Dan caught 0.6 kg.

Step-by-step explanation:

Set up a system of equations:

Don's fish is the variable a and Dan's fish is the variable b.

a + b = 4.2 (1)

a=6b          (2)

We can substitute a in the first equation using the second equation, so:

6b + b = 4.2

7b = 4.2

b = 0.6 kg

Dan caught 0.6 kg. Then, we can use equation 2 to find how much Don caught.

a = 6 x 0.6

a = 3.6

Don caught 3.6 kg.

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3 years ago
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Solve the equations by modeling Draw the steps using circles for the variables and squares for the numbers
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Answer:

A and D

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Step-by-step explanation:

8 0
3 years ago
If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (2, 4, 0) in the direction
valentina_108 [34]

Answer:

a) \nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}.

b) Du_{f}(2,4,0) = -\frac{8}{\sqrt{11}}

Step-by-step explanation:

Given a function f(x,y,z), this function has the following gradient:

\nabla f(x,y,z) = f_{x}(x,y,z)\mathbf{i} + f_{y}(x,y,z)\mathbf{j} + f_{z}(x,y,z)\mathbf{k}.

(a) find the gradient of f

We have that f(x,y,z) = x\sin{yz}. So

f_{x}(x,y,z) = \sin{yz}

f_{y}(x,y,z) = xz\cos{yz}

f_{z}(x,y,z) = xy \cos{yz}.

\nabla f(x,y,z) = f_{x}(x,y,z)\mathbf{i} + f_{y}(x,y,z)\mathbf{j} + f_{z}(x,y,z)\mathbf{k}.

\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}

(b) find the directional derivative of f at (2, 4, 0) in the direction of v = i + 3j − k.

The directional derivate is the scalar product between the gradient at (2,4,0) and the unit vector of v.

We have that:

\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}

\nabla f(2,4,0) = \sin{0}\mathbf{i} + 0\cos{0}\mathbf{j} + 8 \cos{0}\mathbf{k}.

\nabla f(2,4,0) = 0i+0j+8k=(0,0,8)

The vector is v = i + 3j - k = (1,3,-1)

To use v as an unitary vector, we divide each component of v by the norm of v.

|v| = \sqrt{1^{2} + 3^{2} + (-1)^{2}} = \sqrt{11}

So

v_{u} = (\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}})

Now, we can calculate the scalar product that is the directional derivative.

Du_{f}(2,4,0) = (0,0,8).(\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}}) = -\frac{8}{\sqrt{11}}

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