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Archy [21]
3 years ago
10

How do you divide 4/3 by 1.5

Mathematics
2 answers:
zlopas [31]3 years ago
8 0

Answer:

8 /9

Step-by-step explanation:Conversion a decimal number to a fraction: 1.5 = 15

10

= 3

2

Divide: 4 /3

: 1.5 = 4 /3 · 2 /3

= 4/3 · 2 /3

= 8 /9

To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.

bixtya [17]3 years ago
3 0

Answer:

0.9

Step-by-step explanation:

4/3 by 1.5

to divide 4/3, we have to convert it to decimal too

so 4/3 = 1.333 repeatedly

4/3 by 1.5=1.333/1.5

0.8886

0.9 approximately

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Given: ∠AOC, ∠BOC - complementary angles
34kurt

Answer:

  • 30
  • COB . . . . or . . . . BOC

Step-by-step explanation:

The reason given on the line of interest is "substitution," so the problem boils down to determining what was substituted for what. The previous statement says ...

  AOC + COB = 90

and the first part of the statement we're to complete has BOC + ___.

We see from the given statements that m∠AOC = m∠BOC + 30°, so it appears that is the substitution that has been made: AOC has been replaced by BOC + 30.

This means the first blank is filled with 30.

__

The second part of the previous statement is ...

  AOC + COB = 90

so we believe this (COB) should go in the second blank.

__

Then the line of interest would read ...

  BOC + 30 + COB = 90

_____

<em>Comment on the problem</em>

There is a curious mix of notations here. Usually, (as in the beginning of this problem) we refer to the measure of an angle using "m∠" in front of the angle designator, and we use a degree symbol to indicate the units of that measure. Part-way through the problem statement written here, those notations were dropped, and we're to assume they are intended. IMO, this is a poor way to demonstrate careful problem solving.

The substitution given for AOC is BOC+30, but the line into which that is substituted has AOC +COB = 90. This means the equation after substitution is ...

  BOC +30 +COB = 90

Since BOC and COB are the same angle, we can sort of fudge the "algebra" to get to  BOC=30, but if the problem were more carefully written, the angle would be referred to by consistent nomenclature:

  m∠AOC + m∠BOC = 90° . . . . . . . . . preferred angle designations

  (m∠BOC + 30°) + m∠BOC = 90° . . . . substitution for m∠AOC

  2(m∠BOC) = 60° . . . . . . algebra (subtract 30°, collect terms)

  m∠BOC = 30° . . . . . . . . algebra (divide by 2)

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