Answer:
61.5096 %
Explanation:
Let the amount of gold in the jewelry = x g
Let the amount of silver in the jewelry = y g
Total mass of jewelry = 9.85 g
So,
x + y = 9.85 g .................................1
Density = Mass / Volume
Given that:
Density of gold = 19.3 g/cm³
Thus, volume is:
Volume = Mass / Density = x / 19..3 cm³
Given that:
Density of silver = 10.5 g/cm³
Thus, volume is:
Volume = Mass / Density = y / 10.5 cm³
The total volume of the jewelry = 0.675 cm³
So,
Or,
10.5 x + 19.3 y = 136.78875 ................2
Solving 1 and 2, we get that:
<u>x = 6.0587 g</u>
<u>y = 3.7913 g</u>
So, mass % of gold:
<u>Mass % = (6.0587 / 9.85)×100 = 61.5096 %</u>
Answer:
option 1
Explanation:
you can never have all your reactants used up coz it is not possible eg in space u only loose SOme of gravity
Drop out my dude whatever this is ain’t worth it
Answer:
The number of atoms in 1 mole silver is also 6.022 *10^23 atoms.
Option C is correct.
Explanation:
Step 1: Data given
Mass of 1 mole silver = 107.9 grams
Step 2: Calculate the number of atoms in 1 mole of silver
To calculate the number of atoms in 1 mole, we multiply the number of Avogadro by the number of moles
Number of atoms = 1 mol * 6.022 *10^23 atoms/ mol
Number of atoms = 6.022 * 10^23 atoms
Since the number of Avogadro says there are 6.022 * 10^23 atoms per 1 mole. The number of atoms in 1 mole silver is also 6.022 *10^23 atoms.
Option C is correct.
Answer:
0.46M NaS₂O₃ (Assuming KIO₃ solution with a concentration of 1.0M)
Explanation:
Based on the reaction:
6 Na₂S₂O₃ + KIO₃ + 5 KI + 3 H₂SO₄ → 3 Na₂S₄O₆ + 3 H₂O + 3 K₂SO₄ + 6 NaI
<em>6 moles of Na₂S₂O₃ react per mole of KIO₃</em>
Assuming the molarity of the KIO₃ solution is 0,1M:
Moles of KIO₃: = 5.0x10⁻³L ₓ (0.1 mol / L) = <em>5.0x10⁻⁴ moles</em>
As 6 moles of thiosulfate reacted per mole of iodate:
5.0x10⁻⁴ moles KIO₃ ₓ (6 moles Na₂S₂O₃ / 1 mole KIO₃) =
<em>3.0x10⁻³ moles of Na₂S₂O₃. </em>In 6.5mL (6.5x10⁻³L):
3.0x10⁻³moles Na₂S₂O₃ / 6.5x10⁻³ L = 0.46M NaS₂O₃
