Given:
AB is the diameter of a circle.
m∠CAB = 26°
To find:
The measure of m∠CBA.
Solution:
Angle formed in the diameter of a circle is always 90°.
⇒ m∠ACB = 90°
In triangle ACB,
Sum of the angles in the triangle = 180°
m∠CAB + m∠ACB + m∠CBA = 180°
26° + 90° + m∠CBA = 180°
116° + m∠CBA = 180°
Subtract 116° from both sides.
116° + m∠CBA - 116° = 180° - 116°
m∠CBA = 64°
The measure of m∠CBA is 64°.
Answer:
g(1) = -6
Step-by-step explanation:
g(x) = -2x^2 - 4x
You want to solve for g(1). To do this make every x value in the original equation become 1.
g(1) = -2(1)^2 - 4(1)
Evaluate the exponent.
g(1) = -2(1) - 4(1)
Multiply.
g(1) = -2 - 4
Subtract.
g(1) = -6
Answer:
The image of the triangle is smaller than the triangle.
Step-by-step explanation:
We have that
<span>f(x) = (3/2)*x + 4
case 1) for x=-8</span>f(-8) = (3/2)*(-8) + 4--------> -8
point (-8,-8)
case 2) for x=-4f(-4) = (3/2)*(-4) + 4--------> -2
point (-4,-2)
case 3) for x=-2f(-2) = (3/2)*(-2) + 4--------> 1
point (-2,1)
case 4) for x=0f(0) = (3/2)*(0) + 4--------> 4
point (0,4)
case 5) for x=2f(2) = (3/2)*(2) + 4--------> 7
point (2,7)
case 6) for x=4f(4) = (3/2)*(4) + 4--------> 10
point (4,10)
using a graph tool
see the attached figure