F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
You have 50 ways because if there are 10 different types of prizes with 5 prizes you can just multiply that to get your different ways to select the prizes.
Respuesta:
Kansas, Misuri = 8
Paradise, Michigan = 3
Explicación paso a paso:
El rango intercuartílico (IQR) = Q3 - Q1
Q3 = 3/4 (n + 1) th término
n = número de muestras
Q1 = 1/4 (n + 1) th término
Kansas Misuri:
23,25,28,28,32,33,35
Datos pedidos: 23, 25, 28, 28, 32, 33, 35
n = 7
Q1 = 1/4 * 8 = 2do trimestre = 25
Q3 = 3/4 * 8 = 6. ° tem = 33
Q1 = 33 - 25 = 8
Paradise, Michigan:
16,24,26,26,26,27,28
Datos pedidos: 16,24,26,26,26,27,28
Q1 = 1/4 * 8 = 2do = 24
Q3 =. 3/4 * 8 = 6to = 27
Q3 - Q1 = 27 - 24 = 3
Answer:
The answer is below
Step-by-step explanation:
a company decided to increase the size of the box for the packaging of their alcohol products. the length of the original packaging box was 40 cm longer than its width and the height 12 cm, volume was at most 4800 cm3. Suppose the length of the new packaging box is still 40cm longer than its width and the height is 12cm, what mathematical statement would represent the volume of the new packaging box?
Solution:
Let the width of the box be x cm.
The length of the box is 40 cm longer than the width, therefore the length of the box = x + 40
The height of the box = 12 cm
The volume of the box can be gotten from the formula:
Volume = length × width × height
Substituting:
Volume = (x + 40) × (x) × 12
Volume = 12x(x + 40)
Therefore the volume of the new box is 12x(x + 40)
Answer:
Step-by-step explanation:
- Mass = Density*Volume
- V = m/d
- V = 378.24/2.76 = 137.04 cm³ (rounded)
