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Elena L [17]
3 years ago
10

Determine whether the systems have one solution, no solution or infinitely solutions

Mathematics
1 answer:
larisa [96]3 years ago
6 0
Problem would be easier to do if you'd write one function above the other:

<span>3x-2y=3; 6x-4y=1 should be:

</span><span>3x-2y=3
</span><span>6x-4y=1
------------


Please note that if you mult. the first equation by 2, you get 6x-4y= 6, which is almost but not quite the same as the second equation.  
It should be obvious that 6x-4 in the first equation are the same expression as 6x-4 in the second equation.  6x-4 cannot = 6 and also =1 at the same time, so this system has NO solution.  The 2 lines never intersect.

</span>
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I have no idea what to do
tekilochka [14]

Answer: Y=-5x+30

Step-by-step explanation:

First, you have to find the slope of graph so you find the rise over run Y/X. Since the X values are being measured by 1’s, and the Y values are being measure by 5’s, your slope would be -5 (not 5 as the graph line is decreasing therefore it is negative). To find b, you find the Y intercept of the graph (where Y is when X=0) and in this case, the y intercept is 30. So the equation that describes what is occurring in the graph is Y=-5x+30 as a linear equation is written as Y=mx+b. You can check If the equation is correct by substituting the x and y values of a specific coordinate point on the graph. For example: 25= -5(1)+30. This gives you 25=25 so the equation is correct.

8 0
3 years ago
If a = {6 6 4 7 -4 4 -6 9 -3} and B= {1 5 -8 9 -5 -8 9 -5 2}, find 3a +9B Matrix operations
V125BC [204]

Answer:

3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}

Step-by-step explanation

  • A=\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix}\: and \: B=\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}

  • \rightarrow 3A=3\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix},\:  \: 9B =9\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}

  • \rightarrow 3A=\begin{bmatrix} 3*6 & 3*6 & 3*4\\\\3*7 & 3(-4) & 3*4\\\\ 3(-6) & 3*9 & 3(-3)\end{bmatrix},\:\: 9B =\begin{bmatrix}9*1 &9* 5 &9( -8)\\\\ 9*9 & 9(-5) & 9(-8)\\\\ 9*9 & 9(-5) & 9*2\end{bmatrix}

  • \rightarrow 3A=\begin{bmatrix} 18 & 18 & 12 \\\\ 21 & -12 & 12\\\\ -18 & 27 & -9\end{bmatrix},\:\: 9B =\begin{bmatrix} 9 & 45 & -72 \\\\ 81 & -45 & -72\\\\ 81 & -45 & 18\end{bmatrix}

  • \rightarrow 3A+9B=\begin{bmatrix}18+9 & 18+45 & 12+(-72) \\\\ 21+81 & -12 +(-45) & 12+(-72)\\\\ -18+81 & 27+(-45) & -9+18 \end{bmatrix}

  • \rightarrow 3A+9B=\begin{bmatrix} 18+9 & 18+45 & 12-72 \\\\ 21+81 & -12 -45 & 12-72\\\\ -18+81 & 27-45 & -9+18 \end{bmatrix}

  • \rightarrow \purple{\bold{3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}}}
6 0
2 years ago
Tell whether the sequence is arithmetic if it is identify the common difference -9,-17,-26,-33
aleksklad [387]
No it is not, there is no common difference. <span />
8 0
3 years ago
Read 2 more answers
Rearrange to make x the subject of 4(x-3)/a=y
IrinaVladis [17]

Answer: x = a*y + 3

Step-by-step explanation:

To make x the subject of the equation, first, we open the bracket

4x - 12/a = y

Then cross multiply:

4x - 12 = a * y ( a*y means the product of the two variables)

Add 12 to both sides of the equation

4x = a*y + 12

Divide both sides by 4 to get the value of x

x = a * y + 12/4

x = a*y + 3

I hope this helps.

4 0
3 years ago
Statistics how do we determine a percentage
givi [52]
Percent<span> simply means "per hundred" and the symbol used </span>to<span> express </span>percentage<span> is %. One </span>percent<span> (or 1%) is one hundredth of the total or whole and is therefore</span>calculated<span> by dividing the total or whole number by 100. </span>To calculate<span> the </span>percentage<span>difference between two numbers, the same basic calculations are used</span>
7 0
3 years ago
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