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strojnjashka [21]
2 years ago
13

How many triangles can be constructed with sides measuring 15 cm, 7 cm, and 5 cm?

Mathematics
2 answers:
Svetllana [295]2 years ago
5 0

Answer:

none

Step-by-step explanation:

i have proof i just took the test

Viktor [21]2 years ago
4 0

Answer:

More than one

Step-by-step explanation:

Trust me, I know.

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A man owns 3/4 of the share of a business and sells 1/3 of his
quester [9]

Given:

A man owns 3/4 of the share of a business and sells 1/3 of his  shares for Bir 10,000.

To find:

The value of the business in Bir.

Solution:

Let x be the value of the business.

It is given that a man owns 3/4 of the share of a business and sells 1/3 of his  shares for Bir 10,000.

x\times \dfrac{3}{4}\times \dfrac{1}{3}=10000

x\times \dfrac{1}{4}=10000

Multiply both sides by 4.

x=4\times 10000

x=40000

Therefore, the value of the business is 40,000 Bir.

3 0
2 years ago
Mrs. White's students are making school spirit packs. They have 24 bumper stickers and 18 window clings. Every pack must have th
ExtremeBDS [4]

Answer:

6 packet.

Step-by-step explanation:

Given:

Mrs. White's students are making school spirit packs.

They have 24 bumper stickers and 18 window clings.

Every pack must have the same contents and there should be no leftover items.

Question asked:

What is the greatest number of packs they can make?

Solution:

To find the<u> </u><u>greatest number</u> of packs could be made by 24 bumper stickers and 18 window clings by using<u> </u><u>same contents</u> in each pack with<u> </u><u>no left over </u>items, we will simply use<u><em> Highest Common Factor.</em></u>

Factor of 24 - 2, 3, 4, <em><u>6</u></em>, 8, 12, 24

Factor of 18 - 2, 3, <em><u>6</u></em>, 9, 18

Highest Common Factor is 6.

Thus, they can make 6 packet at most.

3 0
2 years ago
Da Pecture 30cm long 25cm wide is pasted
jeka57 [31]

Answer:

A=300cm^2

Step-by-step explanation:

find both areas and subtract the inside area

6 0
2 years ago
If a translation of (x, y) → (x + 6, y – 10) is applied to figure ABCD, what are the coordinates of D'?
Mice21 [21]

Answer:

<em> (x , y) is translated to Horizontal translation right '6' units and </em>

<em>Vertical translation down '10' units      </em>

<em>(x ,y ) →  ( x +6 , y - 10)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<em>Type of Transformation                              Change to co-ordinate point</em>

<em></em>

<em>Vertical translation up 'd' units                         (x, y) → (x , y+d)</em>

<em>Vertical translation down 'd' units                    (x, y) → (x , y-d)</em>

<em>Horizontal translation left 'c' units                  (x ,y ) → (x - c , y)</em>

<em>Horizontal translation right 'c' units              (x ,y ) → (x + c , y)</em>

<em></em>

<em>Given (x , y) is translated to Horizontal translation right '6' units and </em>

<em>Vertical translation down '10' units      </em>

<em>There fore </em>

<em>(x ,y ) →  ( x +6 , y - 10)</em>

7 0
3 years ago
Read 2 more answers
100 POINTS!! OMG YOU NEED TO SOLVE THIS!
natita [175]

Answer:

The correct answer is: \Delta BDE \cong \Delta BFK by <em>rule</em> ASA rule of congruence.

Step-by-step explanation:

First let us prove \Delta BDE \cong \Delta BFK by rule ASA (rule of congruence).

<u>Congruent side:</u>

\overline{BD} \cong \overline{BF} (Given)

<u>Congruent angles:</u>

1. By definition of perpendicular,

\angle{BFK} = 90 \textdegree \ (Since \ \overline{FK} \ is \ perpendicular \ to \ \overline{AB} \ (\overline{FK} \perp \overline{AB} =Given))

Also,

\angle{BDE} = 90 \textdegree \ (Given)

Therefore,

\angle{BDE} \cong \angle{BFK}

or you can say,

\angle{D} \cong \angle{F}

2. Common angle between \Delta BDE \ and \ \Delta BFK is \angle{B}

In a nutshell, in \Delta BDE,

\angle{B} (Angle)

\overline{BD} (Side)

\angle{BDE} (Angle)

are congruent to the following angle, side and angle of \Delta BFK:

\angle{B} (Angle)

\overline{BF} (Side)

\angle{BFK} (Angle)

Therefore, by ASA rule of congruence, we can say \Delta BDE \cong \Delta BFK.

<em>Since both triangles are congruent</em>, the sides \overline{ED} and \overline{FK} are also congruent.

5 0
3 years ago
Read 2 more answers
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