Answer:
I think it’s the second one, 70a+21b sorry if I’m wrong!
Answer:
4.65% probability that a randomly selected customer takes more than 10 minutes
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Probability that a customer takes more than 10 minutes:
This is 1 subtracted by the pvalue of Z when X = 10. So

has a pvalue of 0.9535
1 - 0.9535 = 0.0465
4.65% probability that a randomly selected customer takes more than 10 minutes
Answer:
I believe the first one is rotation And the second is ABC= DEF.
Step-by-step explanation:
My geometry is really rusty so I apologize if they’re wrong
Answer:

Step-by-step explanation:
Setting it up as a fraction will help us see the simplification process a bit easier.

a/a = 1, so they cancel each other out, leaving us with simply
