Short answer
For 6: 72 ft^2
For 7: 650 m^2
Six
The base is a square. It's measurement is s = 4
Base = 4^2
Base = 16 ft^2
One triangle
A = 1/2 * b * h
A = 1/2 * 4 * 7
A = 14 tt^2
Four triangles
A = 4 * 14
A = 56 ft^2
Total Area = 56 + 16 = 72 ft^2
Answer 72 square feet
Seven
Triangles
Area of 1 triangle = 1/2 * 10 * 13
Area of 1 triangle = 65
Area of 6 triangles
Area of 6 triangles = 6 * area of 1 triangle
Area of 6 triangles = 390
Base
As near as I can tell, the base is a hexagon. It's using a rather out of the way method of drawing it. I will assume it is a regular hexagon. The area of a regular hexagon is 3 sqrt(3)/2 * S^2 where s is the side of the hexagon.
Area = 3sqrt(3)/2 s^2
s = 10
Area = 3sqrt(3)/2 10^2
Area = 5.1962 * 100 /2
Area = 259.81
Total area
Total area = area of the base + area of the triangles
Total area = 259.81 + 390
Total area (rounded ) = 650
Answer C <<<< answer
I'll do one more in this batch and then you'll need to repost again.
Eight
If you draw two diagonals on the base of the figure, the intersection point will meet the base of the height. Read that a couple of times.
Join the intersection to the midpoint of the length of the square bottom. You should get 3.5
x is found by using the pythagorean theorem.
h = 6
s = 3.5
x = ????
x^2 = 6^2 + 3.5^2
x^2 = 36 + 12.25
x^2 = 48.25
x = sqrt(48.25)
x = 6.95
C <<<< answer
Almost positive isosceles triangle
Answer:
1) 4+n<13
2) 11-n>17
3) n-8≥9 or n+(-8)≥9
4) 16<8n
5) n·5≤30
Step-by-step explanation:
Answer:
x=3 and y=1
Step-by-step explanation:
subtract equation 2 from 1
then (2x+3y) -(2x+y) =9-7
2x-2x+3y-y =2
2y=2 therefore y=1
substitute y value in 2x+y=7
2x+1=7
2x=7-1
2x=6
x=3
Since each leg of the large trapezoid is bisected, then HJ is the average of the lengths of KL and NM.
HJ = (KL + NM)/2
2(HJ) = KL + nm
2(5x + 2) = 4x + 1 + 27
10x + 4 = 4x + 28
6x = 24
x = 4
KL = 4x + 1 = 4(4) + 1 = 16 + 1 = 17
Answer: KL = 17
